What i'm trying to do is to use grep to search through a few files for a selected daemon and only report on today's date.
I think I got it sorted apart from in the txt file the date has 2 gaps between the month and the day, and the way I have the date format only puts in one gap any help to get the 2 gaps would be greatly received or maybe another method to get the report
Hi Guys.
I am very new to UNIX.
I need to get yesterdays and tommorows date given todays date.
Which command and syntax do i use in basic UNIX shell.
Thanks. (2 Replies)
Daily one file will dropped into this directory.
Directory: /opt/app/jt/drop
File name: XXXX_<timestamp>.dat.gz
I need to write a script which checks whether the file is dropped daily or not.
Any idea in the script how can we compare timestamp of the file to today's date?? (3 Replies)
Hello guys - I am new to Unix.
I am trying to understand how to grep a perticular string in todays file?
I am trying this syntax but not getting what I am looking for:
% grep `date '+%d/%b/%Y'`
For instance there are 2 files generated today with same data. I am trying to find them and... (21 Replies)
Greetings.
I need to generate a simple report via Bash (Korn?) with this raw data
Test_Version=V2.5.2
Test_Version=V2.6.3
Test_Version=V2.4.7
Test_Version=V2.5.2
Test_Version=V2.5.2
Test_Version=V2.5.1
Test_Version=V2.5.0
Test_Version=V2.3.9
... (3 Replies)
Hi Folks,
I have created a script last month to retrive files thru FTP and cronjob was running fine till yesterday. But the naming convention of the daily file is Filename_<date>.xml
where date is YYYYMMDD. But today i have received file name as Filename_20110232.xml :(
Part of my Perl... (4 Replies)
Hello,
I am quite new to unix/shell and want to write a script using bash which will process the files.
Basically i want to search files having name as "date+hostname+somestring.out"
i am using below variables and then will use them in find command :-
TODAY_DATE=$('date +%d')... (5 Replies)
Hi,
I want to compare today's date(DDMMYYYY) with yesterday(DDMMYYYY) from system date,if (today month = yesterday month) then execute alter query else do nothing.
The above requirement i want in Shell script(KSH)...
Can any one please help me?
Double post, continued here. (0 Replies)
I am trying to include a snippet in my script to check if the file created is having today's date.
eg: File name is : ABC.YYYYMMDD-nnn.log
The script should check if 'YYYYMMDD' in the above file name matches with today's date.
Can you please help me in achieving this.
Thanks in advance!! (5 Replies)
hi all,
How to compare two files whether they are same are not...? like i had my input files as 20141201_file.txt and 20141130_file2.txt
how to compare the above files based on date .. like todays file and yesterdays file...? (4 Replies)
Discussion started by: hemanthsaikumar
4 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)