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Top Forums Shell Programming and Scripting Passing parameter from one file to shell script Post 302252291 by joeyg on Wednesday 29th of October 2008 07:23:56 AM
Old 10-29-2008
Hammer & Screwdriver It appears to make sense

Take a look at the following. I inserted the "2*" into the script just to verify/show what was doing the echo.

> cat file1
COUNTRYCODE,LD_DATE
AB,20081210

> cat file2.sh
echo "2*" $1 $2

> while read var1 var2; do file2.sh $var1 $var2; done <file1
2* COUNTRYCODE,LD_DATE
2* AB,20081210
 

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GEOIP_COUNTRY_CODE3_BY_NAME(3)						 1					    GEOIP_COUNTRY_CODE3_BY_NAME(3)

geoip_country_code3_by_name - Get the three letter country code

SYNOPSIS
string geoip_country_code3_by_name (string $hostname) DESCRIPTION
The geoip_country_code3_by_name(3) function will return the three letter country code corresponding to a hostname or an IP address. PARAMETERS
o $hostname - The hostname or IP address whose location is to be looked-up. RETURN VALUES
Returns the three letter country code on success, or FALSE if the address cannot be found in the database. EXAMPLES
Example #1 A geoip_country_code3_by_name(3) example This will print where the host example.com is located. <?php $country = geoip_country_code3_by_name('www.example.com'); if ($country) { echo 'This host is located in: ' . $country; } ?> The above example will output: This host is located in: USA SEE ALSO
geoip_country_code_by_name(3), geoip_country_name_by_name(3). PHP Documentation Group GEOIP_COUNTRY_CODE3_BY_NAME(3)
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