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Top Forums Shell Programming and Scripting usage of echo with standard input Post 302251518 by calandrea on Monday 27th of October 2008 10:21:35 AM
Old 10-27-2008
thanks for your reply
Using var="$1" I get an empty line when trying to display the variable (echo $var)
It works if I run the program with:
program filename
but as I said I have to use a "<" sign
 

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STRVAL(3)								 1								 STRVAL(3)

strval - Get string value of a variable

SYNOPSIS
string strval (mixed $var) DESCRIPTION
Get the string value of a variable. See the documentation on string for more information on converting to string. This function performs no formatting on the returned value. If you are looking for a way to format a numeric value as a string, please see sprintf(3) or number_format(3). PARAMETERS
o $var - The variable that is being converted to a string. $var may be any scalar type or an object that implements the __toString() method. You cannot use strval(3) on arrays or on objects that do not implement the __toString() method. RETURN VALUES
The string value of $var. EXAMPLES
Example #1 strval(3) example using PHP 5's magic __toString() method. <?php class StrValTest { public function __toString() { return __CLASS__; } } // Prints 'StrValTest' echo strval(new StrValTest); ?> SEE ALSO
boolval(3), floatval(3), intval(3), settype(3), sprintf(3), number_format(3), Type juggling, __toString(). PHP Documentation Group STRVAL(3)
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