10-27-2008
thanks for your reply
Using var="$1" I get an empty line when trying to display the variable (echo $var)
It works if I run the program with:
program filename
but as I said I have to use a "<" sign
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STRVAL(3) 1 STRVAL(3)
strval - Get string value of a variable
SYNOPSIS
string strval (mixed $var)
DESCRIPTION
Get the string value of a variable. See the documentation on string for more information on converting to string.
This function performs no formatting on the returned value. If you are looking for a way to format a numeric value as a string, please see
sprintf(3) or number_format(3).
PARAMETERS
o $var
- The variable that is being converted to a string. $var may be any scalar type or an object that implements the __toString()
method. You cannot use strval(3) on arrays or on objects that do not implement the __toString() method.
RETURN VALUES
The string value of $var.
EXAMPLES
Example #1
strval(3) example using PHP 5's magic __toString() method.
<?php
class StrValTest
{
public function __toString()
{
return __CLASS__;
}
}
// Prints 'StrValTest'
echo strval(new StrValTest);
?>
SEE ALSO
boolval(3), floatval(3), intval(3), settype(3), sprintf(3), number_format(3), Type juggling, __toString().
PHP Documentation Group STRVAL(3)