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Top Forums UNIX for Dummies Questions & Answers Grep for a pattern based on another patter Post 302248449 by rock1 on Friday 17th of October 2008 04:38:42 PM
Old 10-17-2008
Grep for a pattern based on another patter

hi,

I have looked at many grep threads and am unable to find something like this: please help.
I have a file which is generated from a report generator and i am trying to load a whole lot of specific data into a table for the users. One field is causing me problems.All the rest i can manage.
I want to grep lines with date: (grep "date:" filename)..
however i want those dates only where there is a TEST in the 7th line below it and before the next pattern(dateSmilie

date: 01/01/2001
xx
yy
zz
aa
bb
cc
TEST
zz
date: 01/02/2001
xx
yy
zz
aa
bb
cc
NOTEST
xx
date: 01/03/2001
xx
yy
zz
aa
bb
cc
NOTEST
yy
date: 01/04/2001
xx
yy
zz
aa
bb
cc
TEST
aa


so the result will be :
date: 01/01/2001
date: 01/04/2001

Any help pl...

thanks
 

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DATE_PARSE_FROM_FORMAT(3)						 1						 DATE_PARSE_FROM_FORMAT(3)

date_parse_from_format - Get info about given date formatted according to the specified format

SYNOPSIS
array date_parse_from_format (string $format, string $date) DESCRIPTION
Returns associative array with detailed info about given date. PARAMETERS
o $format - Format accepted by DateTime.createFromFormat(3). o $date - String representing the date. RETURN VALUES
Returns associative array with detailed info about given date. EXAMPLES
Example #1 date_parse_from_format(3) example <?php $date = "6.1.2009 13:00+01:00"; print_r(date_parse_from_format("j.n.Y H:iP", $date)); ?> The above example will output: Array ( [year] => 2009 [month] => 1 [day] => 6 [hour] => 13 [minute] => 0 [second] => 0 [fraction] => [warning_count] => 0 [warnings] => Array ( ) [error_count] => 0 [errors] => Array ( ) [is_localtime] => 1 [zone_type] => 1 [zone] => -60 [is_dst] => ) SEE ALSO
DateTime.createFromFormat(3), checkdate(3). PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)
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