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Full Discussion: having problem with for loop
Top Forums Shell Programming and Scripting having problem with for loop Post 302247616 by MrC on Thursday 16th of October 2008 05:49:38 AM
Old 10-16-2008
Here's the portion from your while loop:

Code:
while read line
do
    num=$(echo $line | tr -s " " | cut -d " " -f9)
    sum=`expr $sum + $num`
done < <( grep -h $a Archiver* | grep 'ERROR' | grep 'CleanLPDataMessage: Missing Intervals' )
echo "Total CleanLPDataMessage: Missing Intervals is $sum"

But the entire while loop and its process substitution can be done more simply in awk or perl:
Code:
perl -ne 'END {print "Total CleanLPDataMessage: Missing Intervals is $sum\n"} /^'"$a"'.* ERROR - CleanLPDataMessage: Missing Intervals: (\d+)$/ and $sum += $1' Archiver*

All you need to do is to set a, your data variable just as you did above.
MrC
 

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zegrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
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EXIT CODE

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AUTHOR

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SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)
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