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Top Forums Programming How to trim the white space around a string in C program Post 302245708 by redoubtable on Friday 10th of October 2008 06:43:57 PM
Old 10-10-2008
Quote:
Originally Posted by monikersupreme
This code doesn't compile (regcomp throws an error)... is there any way to get regcomp/regexec to recognize whitespace (using "_" doesn't work) or a word boundary?
The code compiles under gcc 4.1.2 Linux. As to the other question, yes it's possible. Try searching google for "POSIX.2 regular expressions" for more information.
 

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REGEXP(2)							System Calls Manual							 REGEXP(2)

NAME
regcomp, regcomplit, regcompnl, regexec, regsub, rregexec, rregsub, regerror - regular expression SYNOPSIS
#include <u.h> #include <libc.h> #include <regexp.h> Reprog *regcomp(char *exp) Reprog *regcomplit(char *exp) Reprog *regcompnl(char *exp) int regexec(Reprog *prog, char *string, Resub *match, int msize) void regsub(char *source, char *dest, Resub *match, int msize) int rregexec(Reprog *prog, Rune *string, Resub *match, int msize) void rregsub(Rune *source, Rune *dest, Resub *match, int msize) void regerror(char *msg) DESCRIPTION
Regcomp compiles a regular expression and returns a pointer to the generated description. The space is allocated by malloc(2) and may be released by free. Regular expressions are exactly as in regexp(6). Regcomplit is like regcomp except that all characters are treated literally. Regcompnl is like regcomp except that the . metacharacter matches all characters, including newlines. Regexec matches a null-terminated string against the compiled regular expression in prog. If it matches, regexec returns 1 and fills in the array match with character pointers to the substrings of string that correspond to the parenthesized subexpressions of exp: match[i].sp points to the beginning and match[i].ep points just beyond the end of the ith substring. (Subexpression i begins at the ith left parenthe- sis, counting from 1.) Pointers in match[0] pick out the substring that corresponds to the whole regular expression. Unused elements of match are filled with zeros. Matches involving and are extended as far as possible. The number of array elements in match is given by msize. The structure of elements of match is: typedef struct { union { char *sp; Rune *rsp; }; union { char *ep; Rune *rep; }; } Resub; If match[0].sp is nonzero on entry, regexec starts matching at that point within string. If match[0].ep is nonzero on entry, the last character matched is the one preceding that point. Regsub places in dest a substitution instance of source in the context of the last regexec performed using match. Each instance of , where n is a digit, is replaced by the string delimited by match[n].sp and match[n].ep. Each instance of is replaced by the string delim- ited by match[0].sp and match[0].ep. Regerror, called whenever an error is detected in regcomp, regexec, or regsub, writes the string msg on the standard error file and exits. Regerror can be replaced to perform special error processing. Rregexec and rregsub are variants of regexec and regsub that use strings of Runes instead of strings of chars. With these routines, the rsp and rep fields of the match array elements should be used. SOURCE
/sys/src/libregexp SEE ALSO
grep(1) DIAGNOSTICS
Regcomp returns 0 for an illegal expression or other failure. Regexec returns 0 if string is not matched. BUGS
There is no way to specify or match a NUL character; NULs terminate patterns and strings. REGEXP(2)
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