Sponsored Content
Full Discussion: Sed variables
Top Forums Shell Programming and Scripting Sed variables Post 302243729 by Zenwork on Monday 6th of October 2008 12:12:07 PM
Old 10-06-2008
Great - a followup question

That works great...Smilie

But now I need to add a leading and a trailing characters between the lines...

ex.

<p>dog</p>
<p>cat</p>
<p>mouse</p>

Thanks for your help in advance....
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

doing a sed with variables

Hi, I'm trying to do the following , I have certain variables in a file and then I want to check for these variables in a certain cobol file to see if they contain a certain package if so replace them with value 1 but but that last line is giving problems: # for each variable in SQL file ... (1 Reply)
Discussion started by: seaten
1 Replies

2. Shell Programming and Scripting

doing a sed with variables

Hi, I'm trying to do the following , I have certain variables in a file and then I want to check for these variables in a certain cobol file to see if they contain a certain package if so replace them with value 1 but but that last line is giving problems: # for each variable in SQL file ... (1 Reply)
Discussion started by: seaten
1 Replies

3. UNIX for Dummies Questions & Answers

doing a sed on certain variables

Hi guys, I want to replace certain values with the number 1. But it is also replacing other values which contain the value I want to replace. e.g.: I want to replace ID-INTERNAL with 1, that's no problem but it will also replace ID-INTERNAL-NON-REM with 1-NON-REM I don't want to... (10 Replies)
Discussion started by: seaten
10 Replies

4. Shell Programming and Scripting

variables in sed

when i do something like substituting a particular thing with a system variable, i am unable to do that expect the varible name getting into that. for ex.. i tried, sed -e 's/date/`date`/g' <if >of but i got date replaced with "`date`" and not with the actual date .. same case happened... (5 Replies)
Discussion started by: sskb
5 Replies

5. Shell Programming and Scripting

Using sed with variables (again!)

Hi, I'm trying to use sed to delete the last three lines of a file. I currently have: # get the amount of lines in the file foldernum=`wc -l File_In.txt | cut -c1-8` # remove the lines in the file sed "${foldernum}-3,${foldernum}d" File_In.txt > File_Out.txt I get the error - sed:... (5 Replies)
Discussion started by: Mr_Plow
5 Replies

6. Shell Programming and Scripting

using variables with sed

I'm trying to get sed to cut and replace using variables, but it doesnt seem to work, when I run this the mod time of the file does get updated. Is my syntax incorrect in the sed command? Thanks #!/usr/bin/ksh #Modify header set -x HEAD=$(cat PBN2CPR1.TXT | awk 'BEGIN { FS = ","... (1 Reply)
Discussion started by: ddurden7
1 Replies

7. UNIX for Dummies Questions & Answers

sed using variables

Hi, I am able to use sed if I hardcode the find and replace values in a shell script. This works: sed -e 's/123v/4567/g' /path/aaa.txt > /path/aaa.txt.tmp If I use a variable, I am not able to use sed command. why? This doesnot work: i=abc j=bk${i} sed -e 's/${i}/${j}/g'... (5 Replies)
Discussion started by: new_learner
5 Replies

8. Shell Programming and Scripting

variables and sed

Is it possible to place a variable in a sed command as such? sed 's/ret_Priv()/$var/' <filename> I am doing this under Bourne. (5 Replies)
Discussion started by: plslakewood
5 Replies

9. Shell Programming and Scripting

Using Variables with SED

All I am trying to produce the following in /etc/ssh/sshd_config, # IPv4 only #ListenAddress 0.0.0.0 # IPv4 & IPv6 ListenAddress :: to # IPv4 only ListenAddress <user-entry> ListenAddress <user-entry> # IPv4 & IPv6 #ListenAddress :: The number of user entries can vary. ... (1 Reply)
Discussion started by: miyoung999
1 Replies

10. Shell Programming and Scripting

sed with variables

Im trying to use sed to print value that matches the value in variable and all lines after that. grep "Something" test.txt | sed -e '/{$variable}/,$b' -e 'd' I cant get it work, if I replace the $variable with the value it contains, it works fine... (10 Replies)
Discussion started by: olkkis
10 Replies
PERLREQUICK(1)						 Perl Programmers Reference Guide					    PERLREQUICK(1)

NAME
perlrequick - Perl regular expressions quick start DESCRIPTION
This page covers the very basics of understanding, creating and using regular expressions ('regexes') in Perl. The Guide Simple word matching The simplest regex is simply a word, or more generally, a string of characters. A regex consisting of a word matches any string that contains that word: "Hello World" =~ /World/; # matches In this statement, "World" is a regex and the "//" enclosing "/World/" tells Perl to search a string for a match. The operator "=~" associates the string with the regex match and produces a true value if the regex matched, or false if the regex did not match. In our case, "World" matches the second word in "Hello World", so the expression is true. This idea has several variations. Expressions like this are useful in conditionals: print "It matches " if "Hello World" =~ /World/; The sense of the match can be reversed by using "!~" operator: print "It doesn't match " if "Hello World" !~ /World/; The literal string in the regex can be replaced by a variable: $greeting = "World"; print "It matches " if "Hello World" =~ /$greeting/; If you're matching against $_, the "$_ =~" part can be omitted: $_ = "Hello World"; print "It matches " if /World/; Finally, the "//" default delimiters for a match can be changed to arbitrary delimiters by putting an 'm' out front: "Hello World" =~ m!World!; # matches, delimited by '!' "Hello World" =~ m{World}; # matches, note the matching '{}' "/usr/bin/perl" =~ m"/perl"; # matches after '/usr/bin', # '/' becomes an ordinary char Regexes must match a part of the string exactly in order for the statement to be true: "Hello World" =~ /world/; # doesn't match, case sensitive "Hello World" =~ /o W/; # matches, ' ' is an ordinary char "Hello World" =~ /World /; # doesn't match, no ' ' at end Perl will always match at the earliest possible point in the string: "Hello World" =~ /o/; # matches 'o' in 'Hello' "That hat is red" =~ /hat/; # matches 'hat' in 'That' Not all characters can be used 'as is' in a match. Some characters, called metacharacters, are reserved for use in regex notation. The metacharacters are {}[]()^$.|*+? A metacharacter can be matched by putting a backslash before it: "2+2=4" =~ /2+2/; # doesn't match, + is a metacharacter "2+2=4" =~ /2+2/; # matches, + is treated like an ordinary + 'C:WIN32' =~ /C:\WIN/; # matches "/usr/bin/perl" =~ //usr/bin/perl/; # matches In the last regex, the forward slash '/' is also backslashed, because it is used to delimit the regex. Non-printable ASCII characters are represented by escape sequences. Common examples are " " for a tab, " " for a newline, and " " for a carriage return. Arbitrary bytes are represented by octal escape sequences, e.g., "33", or hexadecimal escape sequences, e.g., "x1B": "1000 2000" =~ m(0 2) # matches "cat" =~ /143x61x74/ # matches in ASCII, but a weird way to spell cat Regexes are treated mostly as double-quoted strings, so variable substitution works: $foo = 'house'; 'cathouse' =~ /cat$foo/; # matches 'housecat' =~ /${foo}cat/; # matches With all of the regexes above, if the regex matched anywhere in the string, it was considered a match. To specify where it should match, we would use the anchor metacharacters "^" and "$". The anchor "^" means match at the beginning of the string and the anchor "$" means match at the end of the string, or before a newline at the end of the string. Some examples: "housekeeper" =~ /keeper/; # matches "housekeeper" =~ /^keeper/; # doesn't match "housekeeper" =~ /keeper$/; # matches "housekeeper " =~ /keeper$/; # matches "housekeeper" =~ /^housekeeper$/; # matches Using character classes A character class allows a set of possible characters, rather than just a single character, to match at a particular point in a regex. Character classes are denoted by brackets "[...]", with the set of characters to be possibly matched inside. Here are some examples: /cat/; # matches 'cat' /[bcr]at/; # matches 'bat', 'cat', or 'rat' "abc" =~ /[cab]/; # matches 'a' In the last statement, even though 'c' is the first character in the class, the earliest point at which the regex can match is 'a'. /[yY][eE][sS]/; # match 'yes' in a case-insensitive way # 'yes', 'Yes', 'YES', etc. /yes/i; # also match 'yes' in a case-insensitive way The last example shows a match with an 'i' modifier, which makes the match case-insensitive. Character classes also have ordinary and special characters, but the sets of ordinary and special characters inside a character class are different than those outside a character class. The special characters for a character class are "-]^$" and are matched using an escape: /[]c]def/; # matches ']def' or 'cdef' $x = 'bcr'; /[$x]at/; # matches 'bat, 'cat', or 'rat' /[$x]at/; # matches '$at' or 'xat' /[\$x]at/; # matches 'at', 'bat, 'cat', or 'rat' The special character '-' acts as a range operator within character classes, so that the unwieldy "[0123456789]" and "[abc...xyz]" become the svelte "[0-9]" and "[a-z]": /item[0-9]/; # matches 'item0' or ... or 'item9' /[0-9a-fA-F]/; # matches a hexadecimal digit If '-' is the first or last character in a character class, it is treated as an ordinary character. The special character "^" in the first position of a character class denotes a negated character class, which matches any character but those in the brackets. Both "[...]" and "[^...]" must match a character, or the match fails. Then /[^a]at/; # doesn't match 'aat' or 'at', but matches # all other 'bat', 'cat, '0at', '%at', etc. /[^0-9]/; # matches a non-numeric character /[a^]at/; # matches 'aat' or '^at'; here '^' is ordinary Perl has several abbreviations for common character classes. (These definitions are those that Perl uses in ASCII-safe mode with the "/a" modifier. Otherwise they could match many more non-ASCII Unicode characters as well. See "Backslash sequences" in perlrecharclass for details.) o d is a digit and represents [0-9] o s is a whitespace character and represents [ f] o w is a word character (alphanumeric or _) and represents [0-9a-zA-Z_] o D is a negated d; it represents any character but a digit [^0-9] o S is a negated s; it represents any non-whitespace character [^s] o W is a negated w; it represents any non-word character [^w] o The period '.' matches any character but " " The "dswDSW" abbreviations can be used both inside and outside of character classes. Here are some in use: /dd:dd:dd/; # matches a hh:mm:ss time format /[ds]/; # matches any digit or whitespace character /wWw/; # matches a word char, followed by a # non-word char, followed by a word char /..rt/; # matches any two chars, followed by 'rt' /end./; # matches 'end.' /end[.]/; # same thing, matches 'end.' The word anchor "" matches a boundary between a word character and a non-word character "wW" or "Ww": $x = "Housecat catenates house and cat"; $x =~ /cat/; # matches cat in 'catenates' $x =~ /cat/; # matches cat in 'housecat' $x =~ /cat/; # matches 'cat' at end of string In the last example, the end of the string is considered a word boundary. Matching this or that We can match different character strings with the alternation metacharacter '|'. To match "dog" or "cat", we form the regex "dog|cat". As before, Perl will try to match the regex at the earliest possible point in the string. At each character position, Perl will first try to match the first alternative, "dog". If "dog" doesn't match, Perl will then try the next alternative, "cat". If "cat" doesn't match either, then the match fails and Perl moves to the next position in the string. Some examples: "cats and dogs" =~ /cat|dog|bird/; # matches "cat" "cats and dogs" =~ /dog|cat|bird/; # matches "cat" Even though "dog" is the first alternative in the second regex, "cat" is able to match earlier in the string. "cats" =~ /c|ca|cat|cats/; # matches "c" "cats" =~ /cats|cat|ca|c/; # matches "cats" At a given character position, the first alternative that allows the regex match to succeed will be the one that matches. Here, all the alternatives match at the first string position, so the first matches. Grouping things and hierarchical matching The grouping metacharacters "()" allow a part of a regex to be treated as a single unit. Parts of a regex are grouped by enclosing them in parentheses. The regex "house(cat|keeper)" means match "house" followed by either "cat" or "keeper". Some more examples are /(a|b)b/; # matches 'ab' or 'bb' /(^a|b)c/; # matches 'ac' at start of string or 'bc' anywhere /house(cat|)/; # matches either 'housecat' or 'house' /house(cat(s|)|)/; # matches either 'housecats' or 'housecat' or # 'house'. Note groups can be nested. "20" =~ /(19|20|)dd/; # matches the null alternative '()dd', # because '20dd' can't match Extracting matches The grouping metacharacters "()" also allow the extraction of the parts of a string that matched. For each grouping, the part that matched inside goes into the special variables $1, $2, etc. They can be used just as ordinary variables: # extract hours, minutes, seconds $time =~ /(dd):(dd):(dd)/; # match hh:mm:ss format $hours = $1; $minutes = $2; $seconds = $3; In list context, a match "/regex/" with groupings will return the list of matched values "($1,$2,...)". So we could rewrite it as ($hours, $minutes, $second) = ($time =~ /(dd):(dd):(dd)/); If the groupings in a regex are nested, $1 gets the group with the leftmost opening parenthesis, $2 the next opening parenthesis, etc. For example, here is a complex regex and the matching variables indicated below it: /(ab(cd|ef)((gi)|j))/; 1 2 34 Associated with the matching variables $1, $2, ... are the backreferences "g1", "g2", ... Backreferences are matching variables that can be used inside a regex: /(www)sg1/; # find sequences like 'the the' in string $1, $2, ... should only be used outside of a regex, and "g1", "g2", ... only inside a regex. Matching repetitions The quantifier metacharacters "?", "*", "+", and "{}" allow us to determine the number of repeats of a portion of a regex we consider to be a match. Quantifiers are put immediately after the character, character class, or grouping that we want to specify. They have the following meanings: o "a?" = match 'a' 1 or 0 times o "a*" = match 'a' 0 or more times, i.e., any number of times o "a+" = match 'a' 1 or more times, i.e., at least once o "a{n,m}" = match at least "n" times, but not more than "m" times. o "a{n,}" = match at least "n" or more times o "a{n}" = match exactly "n" times Here are some examples: /[a-z]+s+d*/; # match a lowercase word, at least some space, and # any number of digits /(w+)s+g1/; # match doubled words of arbitrary length $year =~ /^d{2,4}$/; # make sure year is at least 2 but not more # than 4 digits $year =~ /^d{4}$|^d{2}$/; # better match; throw out 3 digit dates These quantifiers will try to match as much of the string as possible, while still allowing the regex to match. So we have $x = 'the cat in the hat'; $x =~ /^(.*)(at)(.*)$/; # matches, # $1 = 'the cat in the h' # $2 = 'at' # $3 = '' (0 matches) The first quantifier ".*" grabs as much of the string as possible while still having the regex match. The second quantifier ".*" has no string left to it, so it matches 0 times. More matching There are a few more things you might want to know about matching operators. The global modifier "//g" allows the matching operator to match within a string as many times as possible. In scalar context, successive matches against a string will have "//g" jump from match to match, keeping track of position in the string as it goes along. You can get or set the position with the "pos()" function. For example, $x = "cat dog house"; # 3 words while ($x =~ /(w+)/g) { print "Word is $1, ends at position ", pos $x, " "; } prints Word is cat, ends at position 3 Word is dog, ends at position 7 Word is house, ends at position 13 A failed match or changing the target string resets the position. If you don't want the position reset after failure to match, add the "//c", as in "/regex/gc". In list context, "//g" returns a list of matched groupings, or if there are no groupings, a list of matches to the whole regex. So @words = ($x =~ /(w+)/g); # matches, # $word[0] = 'cat' # $word[1] = 'dog' # $word[2] = 'house' Search and replace Search and replace is performed using "s/regex/replacement/modifiers". The "replacement" is a Perl double-quoted string that replaces in the string whatever is matched with the "regex". The operator "=~" is also used here to associate a string with "s///". If matching against $_, the "$_ =~" can be dropped. If there is a match, "s///" returns the number of substitutions made; otherwise it returns false. Here are a few examples: $x = "Time to feed the cat!"; $x =~ s/cat/hacker/; # $x contains "Time to feed the hacker!" $y = "'quoted words'"; $y =~ s/^'(.*)'$/$1/; # strip single quotes, # $y contains "quoted words" With the "s///" operator, the matched variables $1, $2, etc. are immediately available for use in the replacement expression. With the global modifier, "s///g" will search and replace all occurrences of the regex in the string: $x = "I batted 4 for 4"; $x =~ s/4/four/; # $x contains "I batted four for 4" $x = "I batted 4 for 4"; $x =~ s/4/four/g; # $x contains "I batted four for four" The non-destructive modifier "s///r" causes the result of the substitution to be returned instead of modifying $_ (or whatever variable the substitute was bound to with "=~"): $x = "I like dogs."; $y = $x =~ s/dogs/cats/r; print "$x $y "; # prints "I like dogs. I like cats." $x = "Cats are great."; print $x =~ s/Cats/Dogs/r =~ s/Dogs/Frogs/r =~ s/Frogs/Hedgehogs/r, " "; # prints "Hedgehogs are great." @foo = map { s/[a-z]/X/r } qw(a b c 1 2 3); # @foo is now qw(X X X 1 2 3) The evaluation modifier "s///e" wraps an "eval{...}" around the replacement string and the evaluated result is substituted for the matched substring. Some examples: # reverse all the words in a string $x = "the cat in the hat"; $x =~ s/(w+)/reverse $1/ge; # $x contains "eht tac ni eht tah" # convert percentage to decimal $x = "A 39% hit rate"; $x =~ s!(d+)%!$1/100!e; # $x contains "A 0.39 hit rate" The last example shows that "s///" can use other delimiters, such as "s!!!" and "s{}{}", and even "s{}//". If single quotes are used "s'''", then the regex and replacement are treated as single-quoted strings. The split operator "split /regex/, string" splits "string" into a list of substrings and returns that list. The regex determines the character sequence that "string" is split with respect to. For example, to split a string into words, use $x = "Calvin and Hobbes"; @word = split /s+/, $x; # $word[0] = 'Calvin' # $word[1] = 'and' # $word[2] = 'Hobbes' To extract a comma-delimited list of numbers, use $x = "1.618,2.718, 3.142"; @const = split /,s*/, $x; # $const[0] = '1.618' # $const[1] = '2.718' # $const[2] = '3.142' If the empty regex "//" is used, the string is split into individual characters. If the regex has groupings, then the list produced contains the matched substrings from the groupings as well: $x = "/usr/bin"; @parts = split m!(/)!, $x; # $parts[0] = '' # $parts[1] = '/' # $parts[2] = 'usr' # $parts[3] = '/' # $parts[4] = 'bin' Since the first character of $x matched the regex, "split" prepended an empty initial element to the list. BUGS
None. SEE ALSO
This is just a quick start guide. For a more in-depth tutorial on regexes, see perlretut and for the reference page, see perlre. AUTHOR AND COPYRIGHT
Copyright (c) 2000 Mark Kvale All rights reserved. This document may be distributed under the same terms as Perl itself. Acknowledgments The author would like to thank Mark-Jason Dominus, Tom Christiansen, Ilya Zakharevich, Brad Hughes, and Mike Giroux for all their helpful comments. perl v5.16.3 2013-03-04 PERLREQUICK(1)
All times are GMT -4. The time now is 03:26 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy