10-01-2008
Unfortunately that won't do it. That, as you said is over simplified. I tried it, but gets an empty file.
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LEARN ABOUT DEBIAN
dynarr
DYNARR(3pub) C Programmer's Manual DYNARR(3pub)
NAME
dynarr, dynarr_init, dynarr_resize, dynarr_free - simple dynamic arrays
SYNOPSIS
#include <publib.h>
void dynarr_init(struct dynarr *da, size_t elsize);
int dynarr_resize(struct dynarr *da, size_t newsize);
void dynarr_free(struct dynarr *da);
DESCRIPTION
These functions make it easier to use dynamic arrays, i.e., arrays that are allocated with malloc(3) and resized with realloc(3). Below is
a typical code fragment for implementing a dynamic array that is resized as more input is read.
char *p, *line;
size_t alloc, len;
len = 0;
alloc = 1024;
if ((line = malloc(alloc)) == NULL) abort();
while (fgets(line + len, alloc-len, stdin) != NULL) {
len = strlen(line);
alloc += 1024;
if ((p = realloc(alloc)) == NULL) abort();
alloc = p;
}
(The error handling is intentionally simplified.) Below is the above fragment with the dynarr(3).
struct dynarr da;
dynarr_init(&da);
while (fgets((char *)da.data + da.used, da.alloc-da.len, stdin) != NULL) {
da.used = strlen(da.data);
if (dynarr_resize(&da, da.alloc + 1024) == -1) abort();
}
The code is a bit simpler, and all the memory allocation details and most of the error checking code is hidden away.
The dynamic array is represented by a struct dynarr:
struct dynarr {
void *data;
size_t alloc, used;
};
The interface to the dynamic allocation has intentionally been made unopaque.
dynarr_init initializes a struct dynarr to be an empty array, dynarr_resize sets its size to be newsize, and dynarr_free frees the array
(it will become an empty array again).
RETURNS
dynarr_resize returns -1 if it failed, 0 if it succeeded. It does not change the array in any way if it failed.
SEE ALSO
publib(3), malloc(3), realloc(3), strdup(3)
AUTHOR
Lars Wirzenius (lars.wirzenius@helsinki.fi)
Publib C Programmer's Manual DYNARR(3pub)