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Top Forums Shell Programming and Scripting Transport to another server within a script. Post 302241586 by Sarala Anugu on Monday 29th of September 2008 09:47:21 PM
Old 09-29-2008
Re : Transport to another server within a script.

According your description given below
you have this
server1 - which has the script 'emm' and filename 'file'
server2 - which has the script 'emm'
and you want to do this
1) scp the 'file' to server2 from server1
2) run the script 'emm file' on server2 from server1

If that is your requirement, you can achieve this by
1) scp the file to server2
Quote:
scp $owner@10.252.1.1 file
2) run the script remotely
Quote:
ssh $owner@10.252.1.1 '/export/home/dncs/bin/emm file'
but both these steps would require to login to server2 from server1 which would require the login credentials,
If that bothers you, you can implement the ssh authentication without passwords which is a one time event and a simple 2 step procedure
1) run this command on server1
Quote:
ssh-keygen -t dsa
2) run this command on server2
Quote:
scp ~/.ssh/id_dsa.pub <user>@<server2>:~user/.ssh/authorized_keys
Noe you'll able to connect to server2 from server1 without any password
and run any command on server2 from server1
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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