look into the find command.

man find,,, maybe you can hack some of this script,,,,,, it does not do what you want,, but i think parts of it does-------------------------- look down for the line with "find"

#!/bin/ksh
#
# $0 [-u userID] dir
#
if [[ $setx = "true" ]];then set -x;fi
U_f=false;
for i
do case $1 in
-u*) shift
U_f=true
U=${1};;
-h*) more<<*eof

------------------------------------------------------------------------------------

aha2231
Thu Aug 14 13:59:05 PDT 2008

This script will recursively report out if a file is on tape or if it is on disk
based on ls -s = 256



Usage: $0 [-u $USER ] directory

-u $USER will return only those files owned by $USER
directory requested is $1, or default to current directory

Ex: $0
$0 .
$0 dir
$0 -u $USER dir

------------------------------------------------------------------------------------

*eof
exit;;

-*) echo "\007illegal $0 option $1\007"
$0 -h
exit;;

*) break;;

esac
shift
done


if ${U_f} true; then
U="-user ${U}"
else
U=""
fi

echo USER $USER
echo NODE `hostname`
echo START `date`

dir=${1:-`pwd`}

find ${dir} ${U} -type f -ls | awk ' {


f1="ON %-4s %12.2f %-3s %-7s %-7s %5s %2s %-15s %1s"

flag=$2
s=$7
f=$11
u=$5
month=$8
day=$9
time=$10
group=$6


if(flag=="256" && s/1024 > 256 ) {
q="TAPE"
t[(substr($3,1,1))]++;tsum=tsum+$7
}
else {
q="DISK"
d[(substr($3,1,1))]++;dsum=dsum+$7
}

out1 = sprintf(f1, q, s/1024, "kb", u, group, month, day, time, f)
print out1


}

END{

print tsum/1024/1024/1024 " Gigabytes, and " t["-"] " files are ON TAPE"
print dsum/1024/1024/1024 " Gigabytes, and " d["-"] " files are ON DISK"

}'

exit