You need to do the arithmetic separately, sed doesn't know how to subtract. awk does know; do you get an error message or does it just not do what you want? Maybe you need mawk/nawk/gawk/XPG4 awk if your default awk is a really old "traditional" awk.
For the awk command I didn't get an error message but it didn't do what I wanted.
However, I've played around with the code you provided and I got it to work accordingly.
Hi,
I'm trying to do the following , I have certain variables in a file and then I want to check for these variables in a certain cobol file to see if they contain a certain package if so replace them with value 1 but but that last line is giving problems:
# for each variable in SQL file
... (1 Reply)
Hi,
I'm trying to do the following , I have certain variables in a file and then I want to check for these variables in a certain cobol file to see if they contain a certain package if so replace them with value 1 but but that last line is giving problems:
# for each variable in SQL file
... (1 Reply)
Hi guys,
I want to replace certain values with the number 1.
But it is also replacing other values which contain the value I want to replace. e.g.:
I want to replace ID-INTERNAL with 1, that's no problem but it will also replace ID-INTERNAL-NON-REM with 1-NON-REM
I don't want to... (10 Replies)
when i do something like substituting a particular thing with a system variable, i am unable to do that expect the varible name getting into that.
for ex.. i tried,
sed -e 's/date/`date`/g' <if >of
but i got date replaced with "`date`" and not with the actual date ..
same case happened... (5 Replies)
HELP!!!
I'm keep getting "sed: Function s/PETS/dog cannot be parsed."
I have 2 files that list...
# cat FILE1.txt
dog
cat
mouse
# cat FILE2.txt
my pets are
PETS
I put this into a variable...
# A=`cat FILE1.txt`
# sed "s/PETS/$A" FILE2.txt > FILE3.txt (5 Replies)
I'm trying to get sed to cut and replace using variables, but it doesnt seem to work, when I run this the mod time of the file does get updated. Is my syntax incorrect in the sed command?
Thanks
#!/usr/bin/ksh
#Modify header
set -x
HEAD=$(cat PBN2CPR1.TXT | awk 'BEGIN { FS = ","... (1 Reply)
Hi,
I am able to use sed if I hardcode the find and replace values in a shell script.
This works:
sed -e 's/123v/4567/g' /path/aaa.txt
> /path/aaa.txt.tmp
If I use a variable, I am not able to use sed command. why?
This doesnot work:
i=abc
j=bk${i}
sed -e 's/${i}/${j}/g'... (5 Replies)
All
I am trying to produce the following in /etc/ssh/sshd_config,
# IPv4 only
#ListenAddress 0.0.0.0
# IPv4 & IPv6
ListenAddress ::
to
# IPv4 only
ListenAddress <user-entry>
ListenAddress <user-entry>
# IPv4 & IPv6
#ListenAddress ::
The number of user entries can vary.
... (1 Reply)
Im trying to use sed to print value that matches the value in variable and all lines after that.
grep "Something" test.txt | sed -e '/{$variable}/,$b' -e 'd'
I cant get it work, if I replace the $variable with the value it contains, it works fine... (10 Replies)
Discussion started by: olkkis
10 Replies
LEARN ABOUT DEBIAN
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)