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Top Forums Shell Programming and Scripting removing and rounding up decimals Post 302235084 by vino on Thursday 11th of September 2008 06:14:58 AM
Old 09-11-2008
Quote:
Originally Posted by aismann
Hi Experts,

I have a command that gives me the output as below
Code:
root@ckpgpay11core> cat sara | awk '{ sum += $1} ; END { print sum }' | awk {'print $1/90'}
8.88889

how do i remove the decimal spaces so that the figure will round itself to 9?

Thanks.
Using awk

Code:
[/tmp]$ echo "8.8889" | awk '{printf "%.0f\n", $1}'
9

 

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FEGETROUND(3)						   BSD Library Functions Manual 					     FEGETROUND(3)

NAME
fegetround, fesetround -- functions providing access to the floating-point rounding mode. SYNOPSIS
#include <fenv.h> #pragma STDC FENV_ACCESS ON int fegetround(void); int fesetround(int round); DESCRIPTION
These functions provide control of floating-point rounding direction modes. The fegetround() function gets the current rounding direction. It returns the value of the rounding direction macro representing the current rounding direction, or a negative value if either there is no corresponding macro or if the rounding direction is not determinable. The fesetround() function sets the rounding direction to be that specified by the argument round. If the argument is not equal to the value of one of the rounding direction macros, the rounding direction is not changed. It returns zero if and only if the requested rounding direc- tion was established. SEE ALSO
fenv(3), feclearexcept(3), fegetenv(3), fegetexceptflag(3), feholdexcept(3), fesetenv(3), feraiseexcept(3), fesetexceptflag(3), feraiseexcept(3), feupdateenv(3) STANDARDS
These functions conform to ISO/IEC 9899:TC3. BSD
May 9, 2011 BSD
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