09-02-2008
Quote:
The sed script works here, not sure how to fix it. Can you identify which part gives the error? (Try remove parts of the script starting from the end, until you no longer get the error message.) I'm guessing you might need to tweak the number of backslashes in s/\\/\\\\/g but that's a cheap shot.
I exited shell, and started it again and got it to work, not entirely sure why it didn't work before, but it does now!
Thanks for the assistance, it does exactly what I want it to now.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I m trying to pass variable to sed.
export var=140920060731
sed -e '/$var/d' file
but no luch so far..? any body has any idea abt it
Is there any way to pass variable to SED?
Thanks ,
Manish (2 Replies)
Discussion started by: Manish Jha
2 Replies
2. Shell Programming and Scripting
hi,
dataParse(){
line="$@"
name="cat /etc/passwd | grep "$line": | cut -f6 -d':'"
eval $name > sam.txt 2>&1
sudo -u $line sed -n 's/data-1/&/p' $name/test.xml >> sam1.txt
}
Here i getting the homedir of the accounts and is set in
name variable.which returns "/home/raju" which i... (3 Replies)
Discussion started by: sachin.tendulka
3 Replies
3. Shell Programming and Scripting
:confused: Is it possible to send a variable to a sed or cut command? I have a test script as below:
counter=1
while read line
do
# Test the file
printf "$line" > temp$counter
pref=$(cut c1-2000 $temp$counter | sed 's///g' | sed 's|.*PutTime\(.*)Origin.*|\1|')
printf" let... (5 Replies)
Discussion started by: gugs
5 Replies
4. Shell Programming and Scripting
Dear All,
I want to print a file.
First I tried with this
sed '2q;d' filename
it worked. But when i put following it is not working
x=2;
sed '$xq;d' filename
Would any one suggest how to pass the variable? (7 Replies)
Discussion started by: saifurshaon
7 Replies
5. Shell Programming and Scripting
Hi guys,
I wanted to pass a variable to the sed command which tells which line to be deleted.
a=2;
echo $a;
sed '$ad' c.out
it is throwing an error.
sed: 0602-403 "$a"d is not a recognized function.
I even tried "$a" and \$a.. but it is of no use.
Can you please correct me... (6 Replies)
Discussion started by: mac4rfree
6 Replies
6. Shell Programming and Scripting
Within a shell im starting a terdata BTEQ session
#!/bin/ksh
set -x
TEMP_DATABASE=`head -6 /home/karthik/para.txt|tail -1`
TEMP_TABLE=`head -7 /home/karthik/para.txt|tail -1`
bteq<<EOF
.LOGON TEST/karthik,********;
.EXPORT FILE=test1.txt;
.set heading ''
.set titledashes off; ... (4 Replies)
Discussion started by: mkarthykeyan
4 Replies
7. Shell Programming and Scripting
Hi,
I am trying to print a specific line in a file through sed or awk. The line number will be passed as a parameter from the previous step. My code looks as below.
TEMP3=`sed -n '$TEMP2p' $FILEPATH/Log.txt`
$TEMP2, I am getting from the previous step which is a numerical value(eg:3).
... (2 Replies)
Discussion started by: satyasrin82
2 Replies
8. Shell Programming and Scripting
Here is my code
#!/bin/bash
username=gnowicki
sed '$s/$/ $username/' < sshd_config 1 <> sshd_config
what this is supposed to do is take the name gnowicki and put it at the end of the last line of the sshd_config and it works except not using the variable, if I put the name "gnowicki" where... (2 Replies)
Discussion started by: slufoot80
2 Replies
9. UNIX for Dummies Questions & Answers
Hi,
I want to pass value of a variable track_line which is the line number to sed. Sed should print the lines starting from track_line till the last
line of the file. I tried the below command but it is not working.
sed -n '${track_line},$p' latest_log_file
I tried using the below too but... (1 Reply)
Discussion started by: nitinupadhyaya8
1 Replies
10. Shell Programming and Scripting
This is part of a larger script where I need to pass only 1 line of a file to the script, based on a variable and not a direct reference.
As part of a for loop :
# for((line=0;line<50;line++)); do
# awk ‘NR==$line' PhraseList.txt; done
... (5 Replies)
Discussion started by: Seth
5 Replies
shift(1) User Commands shift(1)
NAME
shift - shell built-in function to traverse either a shell's argument list or a list of field-separated words
SYNOPSIS
sh
shift [n]
csh
shift [variable]
ksh
* shift [n]
DESCRIPTION
sh
The positional parameters from $n+1 ... are renamed $1 ... . If n is not given, it is assumed to be 1.
csh
The components of argv, or variable, if supplied, are shifted to the left, discarding the first component. It is an error for the variable
not to be set or to have a null value.
ksh
The positional parameters from $n+1 $n+1 ... are renamed $1 ..., default n is 1. The parameter n can be any arithmetic expression that
evaluates to a non-negative number less than or equal to $#.
On this man page, ksh(1) commands that are preceded by one or two * (asterisks) are treated specially in the following ways:
1. Variable assignment lists preceding the command remain in effect when the command completes.
2. I/O redirections are processed after variable assignments.
3. Errors cause a script that contains them to abort.
4. Words, following a command preceded by ** that are in the format of a variable assignment, are expanded with the same rules as a vari-
able assignment. This means that tilde substitution is performed after the = sign and word splitting and file name generation are not
performed.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO
csh(1), ksh(1), sh(1), attributes(5)
SunOS 5.10 15 Apr 1994 shift(1)