Sponsored Content
Top Forums Shell Programming and Scripting login into root from user and execute command through script Post 302230287 by palsevlohit_123 on Friday 29th of August 2008 02:25:50 AM
Old 08-29-2008
$ cat myscript.ksh
ssh -l root HOSTNAME
echo "WELCOME to ROOT"
<do your stuff>
exit


$ sh myscript.ksh >> myscript.log

Will prompt for the password of root and you have to give manually.
 

10 More Discussions You Might Find Interesting

1. SCO

Executing script with root privilages from a user login

I need to regular users to be able to launch a script which does something requiring root privilages. I've tried using chmod 4755 which gives it -rwsr-xr-x permissions but it still can not be run as the regular user. (1 Reply)
Discussion started by: checkpro
1 Replies

2. Shell Programming and Scripting

shell script to execute user command

I don't know why the following shell script doesn't work. Could you please help me out? #!/usr/bin/ksh test="cal > /tmp/tmp.txt 2>&1" $test I know it will work for the following format: #!/usr/bin/ksh cal > /tmp/tmp.txt 2>&1 However, I need to get the command from the user in... (1 Reply)
Discussion started by: redtiger
1 Replies

3. Shell Programming and Scripting

root user command in shell script execute as normal user

Hi All I have written one shell script for GPRS route add is given below named GPRSRouteSet.sh URL="www.google.com" VBURL="10.5.2.211" echo "Setting route for $URL for GPRS" URL_Address=`nslookup $URL|grep Address:|grep -v "#"|awk -F " " '{print $2}'|head -1` echo "Executing ... (3 Replies)
Discussion started by: mnmonu
3 Replies

4. Shell Programming and Scripting

Execute Root command as Normal user

Hi, We need to execute a root commmand to change the expiry period of a user but we are getting error as permission denied Q How can we execute a root command by a normal user ? :mad: any thing or suggestion will be good .... :b: (3 Replies)
Discussion started by: abhishek1979
3 Replies

5. UNIX for Dummies Questions & Answers

Can not login with root user

Hi folks. our developer had a root user and he changed some settings about root user. We have not known what he changed. There is an oracle user, we can login to oracle, no problem. But when we try to login to root user we are getting this error : $ su root Password: bash:... (9 Replies)
Discussion started by: futi
9 Replies

6. Shell Programming and Scripting

How to Login as another user through Shell script from current user[Not Root]

Hi Every body, I would need a shell script program to login as different user and perform some copy commands in the script. example: Supppose ora_toms is the active user ora_toms should be able to run a script where user: ftptomsp pass: XXX should login through and run the commands ... (9 Replies)
Discussion started by: ujjwal27
9 Replies

7. UNIX for Dummies Questions & Answers

Execute a command as root from normal user

Hi , I am trying to stop and start a process using the below code. I have sudo access on my machine ## PID = process id echo "$PASSWD" | sudo -S kill -9 <PID> echo "$PASSWD" | sudo -S /opt/abc/startserver /opt/abc/startserver: error while loading shared libraries: librts.so: cannot open... (6 Replies)
Discussion started by: rakeshkumar
6 Replies

8. Shell Programming and Scripting

Script for login to servers with user name and password and execute commands

I am having the 15 servers which need to do the monitoring Hi I need a shell script, By which i can log in to multiple servers and execute the commands.. I need to specify the username and password in the scripts. Please help me to write the script so that it can login with username and... (5 Replies)
Discussion started by: nandan8a
5 Replies

9. Shell Programming and Scripting

Execute a command with root user

i m logged in with user1 id. i wish to execute the below as root user for which i tried several commands but all of them fail. sudo 'cat /tmp/tmp.file >>/etc/logger' Password: sudo: cat /tmp/tmp.file >>/etc/logger: command not found sudo cat /tmp/tmp.file >>/etc/logger bash:... (5 Replies)
Discussion started by: mohtashims
5 Replies

10. Shell Programming and Scripting

Execute ssh command with additional terminal command to any remote user not working script

Hello i am having an issue with bash script and this is the code now=$(cat hosts1.txt | awk '{print $2;}') while read n ;do ssh root@$now 'useradd test1; echo -e "test1\ntest1" | passwd test1 && echo "test1 ALL=(ALL:ALL) ALL" >> /etc/sudoers' When i execute only part with cat, it... (8 Replies)
Discussion started by: tomislav91
8 Replies
YAPP(1) 						User Contributed Perl Documentation						   YAPP(1)

NAME
yapp - A perl frontend to the Parse::Yapp module SYNOPSYS
yapp [options] grammar[.yp] yapp -V yapp -h DESCRIPTION
yapp is a frontend to the Parse::Yapp module, which lets you compile Parse::Yapp grammar input files into Perl LALR(1) OO parser modules. OPTIONS
Options, as of today, are all optionals :-) -v Creates a file grammar.output describing your parser. It will show you a summary of conflicts, rules, the DFA (Deterministic Finite Automaton) states and overall usage of the parser. -s Create a standalone module in which the driver is included. Note that if you have more than one parser module called from a program, to have it standalone, you need this option only for one of your parser module. -n Disable source file line numbering embedded in your parser module. I don't know why one should need it, but it's there. -m module Gives your parser module the package name (or name space or module name or class name or whatever-you-call-it) of module. It defaults to grammar -o outfile The compiled output file will be named outfile for your parser module. It defaults to grammar.pm or, if you specified the option -m A::Module::Name (see below), to Name.pm. -t filename The -t filename option allows you to specify a file which should be used as template for generating the parser output. The default is to use the internal template defined in Parse::Yapp::Output.pm. For how to write your own template and which substitutions are available, have a look to the module Parse::Yapp::Output.pm : it should be obvious. -b shebang If you work on systems that understand so called shebangs, and your generated parser is directly an executable script, you can specifie one with the -b option, ie: yapp -b '/usr/local/bin/perl -w' -o myscript.pl myscript.yp This will output a file called myscript.pl whose very first line is: #!/usr/local/bin/perl -w The argument is mandatory, but if you specify an empty string, the value of $Config{perlpath} will be used instead. grammar The input grammar file. If no suffix is given, and the file does not exists, an attempt to open the file with a suffix of .yp is tried before exiting. -V Display current version of Parse::Yapp and gracefully exits. -h Display the usage screen. BUGS
None known now :-) AUTHOR
Francois Desarmenien <francois@fdesar.net> COPYRIGHT
(c) Copyright 1998-1999 Francois Desarmenien, all rights reserved. See Parse::Yapp(3) for legal use and distribution rights SEE ALSO
Parse::Yapp(3) Perl(1) yacc(1) bison(1) perl v5.12.1 2001-02-11 YAPP(1)
All times are GMT -4. The time now is 03:13 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy