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Top Forums Shell Programming and Scripting reverse search a text file from a specified line Post 302230067 by era on Thursday 28th of August 2008 02:15:06 PM
Old 08-28-2008
Quote:
Originally Posted by danmero
Code:
awk '/B/{a=$0}/A/ && a {print a;a=""}' file

a will be the last occurrence of B.
Intuitive (-;

Actually the && a is a useful addition, I meant to remember to not forget it, but failed. But you're not printing the A lines at all, did I misunderstand that part of the requirements? (Also actually not clear whether the matches should be printed or somehow collected, say, just collect the line numbers for later processing? Easy enough to do, NR is the current line number in awk.)
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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