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Top Forums Shell Programming and Scripting Accessing awk array from shell Post 302228131 by bateman23 on Saturday 23rd of August 2008 02:51:15 AM
Old 08-23-2008
Accessing awk array from shell

Hi,
i want awk to read a file and place it's content into two arrays. When trying to read these arrays with a "for a in ${source_path[@]} "-Loop it gives the right result. But when trying to access directly (/bin/echo ${source_path[0]}) it doesn't work.

I read "all "the awk threads in this forum and came to two solutions, which both don't work in the desired way. Is there any other way to pass an array from awk back to the shell script? Or what's wrong with my solutions so far?

Any help is appreciated. Thanks in advance, Daniel

First try:
Code:
#!/bin/sh

declare -a source_path
declare -a target_path

source_path=`awk -F';' '{print $1}' backup_path`
target_path=`awk -F';' '{print $2}' backup_path`

# getting the right values
/bin/echo "Sources"
for a in ${source_path[@]} 
do
/bin/echo $a
done

/bin/echo "Target"
for a in ${target_path[@]} 
do
/bin/echo $a
done

#getting the wrong values  concatenated
/bin/echo ${source_path[0]} 
/bin/echo ${target_path[0]}

Also wrong:
Code:
awk -F';' '{ source_path[NR] = $1 } END { print source_path[1]; }' backup_path

/bin/echo ${source_path[0]}

File, to parse:
Code:
/Users/daniel/Documents/Test;/Volumes/Backup/auto/Test;
/Users/daniel/Documents/Test3;/Volumes/Backup/auto/Test3;
/Users/daniel/Documents/Test2;/Volumes/Backup/auto/Test2;

 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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