Hi,
i want awk to read a file and place it's content into two arrays. When trying to read these arrays with a "for a in ${source_path[@]} "-Loop it gives the right result. But when trying to access directly (/bin/echo ${source_path[0]}) it doesn't work.
I read "all "the awk threads in this forum and came to two solutions, which both don't work in the desired way. Is there any other way to pass an array from awk back to the shell script? Or what's wrong with my solutions so far?
Any help is appreciated. Thanks in advance, Daniel
Hello everyonel,
I have an array set like so
num=4
read name
arr=name
I go through while loop to assign different values to different array element from 1 to 4. when I try to access the FIRST element of the array I get the last one first. Like if I say ${arr} it will show the last element... (4 Replies)
Hello,
I wonder if it is possible to pass and use variables from shell environment into sed or awk. I am trying to achieve something similar to the following using sed or awk:
var=some_regular_expression
grep "$var" filename # Will extract lines from filename
The following code,... (3 Replies)
How do I access one of the indices in array tst with the code below?
tst=sprintf("%5.2f",Car / 12)
When I scan thru the array with
for ( i in tst ) { print i,tst }
I get the output of:
vec-7 144
But when I try this in the END
print tst
It looks like it's not set.
What am... (6 Replies)
I am trying to pass a shell array I created to match on values amongst other things.
I have a sample:
#! /bin/ksh
i=0
for id in `cat id.lst`
do
IDs=$id
(( i=i+1 ))
done
cat sqloutput.txt | awk -F, -v ids=$ID '{
# Do stuff
}'
But it looks as if I cannot do this.... (1 Reply)
Hi,
My doubt is how to access array elements..
Situation is as below:
#!/bin/ksh
set -x
typeset -i x=0
typeset -i y=0
typeset -i BID=0
typeset -i count=0
while ] ; do
x=`expr $x + 1`;
hwmgr show scsi > scsi.tmp
while read line; do
set... (1 Reply)
Hi,
I want to access a variable outside the awk program. My program is as below:- I can not access the exact value of k (See the last line of the program).
#!/usr/bin/sh
j=10
k=1
#k is declared outside awk
awk '
BEGIN {
i=1;
j1="'"$j"'"
printf("\n ## Value of j1 is %d ##", j1);
... (2 Replies)
hi all, i've a requirement like this.
i want to access the contents of an array declared in one script,which is a bash script, to a second script which is a perl script.
actually i want a sort of global variable which can be accessed in other script
like environmen variables and also i can... (3 Replies)
Hi all,
I can’t resolve an array element access issue on (Linux/pdksh) .. So I’m positing for advice.By the way - a friend demonstrated to me - same script works as expected under Solaris.
I have been working on a documentation project where many *.jpg screen shots are used in the... (4 Replies)
Hello All,
Can you please help me with the below.
#!/bin/bash
ARR="No Differences In Stage Between HASH_TOTALS & HASH_TOTALS_COMP For UNINUM:0722075 PROVIDER:5 EXTRACT_DT:30-SEP-12 VER_NUM:1"
ARR="No Differences In Stage Between HASH_TOTALS & HASH_TOTALS_COMP For UNINUM:0722075 PROVIDER:5... (14 Replies)
Discussion started by: Ariean
14 Replies
LEARN ABOUT PHP
echo
ECHO(3) 1 ECHO(3)echo - Output one or more stringsSYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)