Hello all -
I have two systems.
1) Linux box running Redhat 8.0
2) Tru64 box running V4.0f
From the Linux box I am remotely mounting a directory (nfs mount) that resides on the Tru64 machine.
The directory that is nfs mounted contains two subdirectories:
my_dir1
my_dir2
I want... (3 Replies)
I am trying to FTP files from windows to UNIX (IBM AIX). After having sent the files to unix server. Permisssion of the files becomes 640 (rw-r-----). I have to manually login to unix and do chmod 644 on the folder to give it permission. Is it possible that the files automaically be set to 644 on... (2 Replies)
In my script, I am creating a file ----> then writting one line (i.e. Timestamp) ----> then FTP'ing. The same script can be executed by many other users.
While other users executing this script, they couldn't Over write this one line (i.e. Timestamp)
My expectation
So I wanted to create a... (2 Replies)
While executing a script, I am not being able to able to create a file as the file with the same name already exists. That existing file is not getting overwritten as I am not the owner of the file. So, Neither am I able to rename the file nor delete the existing file, so as to get my file created.... (2 Replies)
As I understand the file permissions in UNIX is basically
Owner, group, others
Lets assume scott user who's primary group is dev creates a file called test.dat and then grants some privileges on that file...
scott@unix-host> echo "this is a test" > test.dat
scott@unix-host> chmod 640... (4 Replies)
Can any one tell me is there any command to find out who changed the permission of a file Or is there any log file so that i can find out who has changed the permission of a file?
Thanks in Advance:) (7 Replies)
Hi,
A file is transferred from a Windows server(say username : user1) to Unix server via ftp.
In unix, the permission of the file for a user, say user2 will be "-rw-r-----". Since the user1 is the owner of the file, user2 is not able to change the file permission using chmod.
Is there... (5 Replies)
I need my code to compare two different files that are in two completely different directories, How can I do this?
So for example, my code will look at file1 which is in my home directory, and compare the files with those from file2 that is in /abc/adf/adr/afc/adf/file2... does that make sense? (1 Reply)
Greetings,
After a few hours of trial and error, I decide to ask for some help.
I am new to AWK and shell script, so please don't laugh :p
I made the below script, to gather data from some logs and have the output into a CSV file :
#!/bin/sh
#Script to collect Errors
... (9 Replies)
Discussion started by: Yagami_Sama
9 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)