Sponsored Content
Top Forums Shell Programming and Scripting problem with Variable inside SSH Post 302227242 by yongitz on Wednesday 20th of August 2008 11:29:55 PM
Old 08-21-2008
Hi! I do not understand your situation well, can you please elaborate on what are you trying to achieve? If possible, can you post your entire command or script that your having problem with? And what does this
Code:
filename=`find value -l *.csv`

do? By looking at it, it looks like it's not a valid "find" command. I maybe wrong though.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

ksh: A part of variable A's name is inside of variable B, how to update A?

This is what I tried: vara=${varb}_count (( vara += 1 )) Thanks for help (4 Replies)
Discussion started by: pa3be
4 Replies

2. Shell Programming and Scripting

looping a array inside inside ssh is not working, pls help

set -A arr a1 a2 a3 a4 # START ssh -xq $Server1 -l $Username /usr/bin/ksh <<-EOS integer j=0 for loop in ${arr} do printf "array - ${arr}\n" (( j = j + 1 )) j=`expr j+1` done EOS # END ========= this is not giving me correct output. I... (5 Replies)
Discussion started by: reldb
5 Replies

3. Shell Programming and Scripting

Problem in executing a comand liying inside a variable

Hi everyone! I need some help with my shell script :( I am sending a shell command from a html text input to a cgi. Then, I store it into a variable. For example var="ps -axu" echo `$var` This functions properly. But consider the following... var="ps -axu | grep root" Now, I want... (2 Replies)
Discussion started by: Nene
2 Replies

4. UNIX for Dummies Questions & Answers

passing a variable inside a variable to a function

I would like to know how to pass a variable inside a variable to a function. sample code below -------------- for x in 1 9 do check_null $C$x ##call function to check if the value is null if then echo "line number:$var_cnt,... (2 Replies)
Discussion started by: KingVikram
2 Replies

5. Shell Programming and Scripting

Problem storing SSH result in a variable

i have this SSH command which runs perfectly on command prompt in sunOS ssh -o Port=${portno} ${uname}@${server} find ${dir_path} -name '***' output : /usr/local/home/*** My problem is when i run same command in my script #!/usr/bin/ksh res=`ssh -o Port=${portno} ${uname}@${server}... (1 Reply)
Discussion started by: prash184u
1 Replies

6. Shell Programming and Scripting

variable inside variable inside loop headache

Hi Gurus I have a file called /tmp/CMDB which looks like this serial: 0623AN1208 hostname: server1 model: x4100 assetID: 1234 I am writing a for loop that will go through this file line by line creating a variable of itself. Using the first iteration of the loop (i.e. the first line) as... (6 Replies)
Discussion started by: hcclnoodles
6 Replies

7. Shell Programming and Scripting

Problem using ssh inside script

Hi, When runnin the following script it complte successfully with out any problem #!/bin/sh SERV="crm1" for s in $SERV do export WebLogicSessions=`ssh psoft@$s "cd /software/psoft/scripts ; ./getweblogicsessions.sh crm1 8001 PIA | awk '{print $1}' ` echo "Checking number of... (0 Replies)
Discussion started by: yoavbe
0 Replies

8. Shell Programming and Scripting

problem in assigning substr to a variable inside awk

Hi All, I have a fixed-width datafile from which i need to extract value/string starting from some position to the specified length in each of the lines. awk '{print substr($0,x,y)}' datafile --- is working fine but awk 'BEGIN{a=0}{a=substr($0,x,y);print $a}' datafile ---is giving... (3 Replies)
Discussion started by: loggedin.ksh
3 Replies

9. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

10. Shell Programming and Scripting

Problem using variable inside awk

HI, This is the code I am using: awk -v aaa="connect" 'BEGIN {IGNORECASE} /aaa/,/!/ {print NR}' bb This does not throw any error but it does not work. Pls help Thanks. (4 Replies)
Discussion started by: sudvishw
4 Replies
script(1)							   User Commands							 script(1)

NAME
script - make record of a terminal session SYNOPSIS
script [-a] [filename] DESCRIPTION
The script utility makes a record of everything printed on your screen. The record is written to filename. If no file name is given, the record is saved in the file typescript. See WARNINGS. The script command forks and creates a sub-shell, according to the value of $SHELL, and records the text from this session. The script ends when the forked shell exits or when Control-d is typed. OPTIONS
The following option is supported: -a Appends the session record to filename, rather than overwriting it. NOTES
script places everything that appears on the screen in filename, including prompts. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ |CSI |Enabled | +-----------------------------+-----------------------------+ SEE ALSO
attributes(5) WARNINGS
script can pose a security risk when used in directories that are writable by other users (for example, /tmp), especially when run by a privileged user, that is, root. Be sure that typescript is not a link before running script. SunOS 5.10 30 Jan 2004 script(1)
All times are GMT -4. The time now is 03:39 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy