08-19-2008
monthly calculation
pls can anyone help me with this script, the script is below, i need the script to get the previous month result every new month , the problem is that the loop has to be automated to always calculate for previous month .
a=`date "+%Y"` #this year to be used
b=$(date "+%Y%m" --date='49 days ago') #previous month with year to be used
for i in 49 48 47 46 45 44 43 42 41 40 39 38 37 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19
do
g=$(date "+%Y%m%d" --date=''$i' days ago') # n days ago to be used
h="lic"$g*405*.txt #the file name
cd /home/file/lic$a/$b #the directory
#---------- Count information----------#
cat $h|awk -F '|' '$4 ~ /^700[0]/ && $9 == '0' { print $0 }'|awk -F '|' '{ b = count[$1]++; }''{ print b }' >> result$b.txt
done
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LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)
cal_from_jd - Converts from Julian Day Count to a supported calendar
SYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)