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Full Discussion: using variable in a variable
Top Forums Shell Programming and Scripting using variable in a variable Post 302222955 by G.SANDHYA on Friday 8th of August 2008 02:59:06 AM
Old 08-08-2008
hi all

Iam trying to use eval function in unix scripting
#!/bin/ksh
function evalval {

rate=$(( $1 * $2 ) * (1 -( 100 * $3)))
eval [$rate]
}
evalval $*
echo $rate


evalval: syntax error: `*' unexpected

i am getting the above error
can any one correct this?
 

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cfsetispeed(3)						     Library Functions Manual						    cfsetispeed(3)

NAME
cfsetispeed - Sets input baud rate for a terminal LIBRARY
Standard C Library (libc.so, libc.a) SYNOPSIS
#include <termios.h> int cfsetispeed( struct termios *termios_p; speed_t speed); STANDARDS
Interfaces documented on this reference page conform to industry standards as follows: cfsetispeed(): POSIX.1, XPG4, XPG4-UNIX Refer to the standards(5) reference page for more information about industry standards and associated tags. PARAMETERS
Points to a termios structure containing the input baud rate. Specifies the new input baud rate. DESCRIPTION
The cfsetispeed() function sets the input baud rate stored in the structure pointed to by the termios_p parameter to the value specified by the speed parameter. If the input baud rate is set to 0 (zero), the input baud rate will be specified by the value of the output baud rate. There is no effect on the baud rates set in the hardware until a subsequent successful call is made to the tcsetattr() function on the same termios structure. RETURN VALUES
Upon successful completion, the cfsetispeed() function returns a value of 0 (zero). Otherwise, a value of -1 is returned. RELATED INFORMATION
Functions: cfgetispeed(3), cfgetospeed(3), cfsetospeed(3), tcsetattr(3) Files: termios(4) Standards: standards(5) delim off cfsetispeed(3)
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