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Top Forums UNIX for Dummies Questions & Answers multiplication shows syntax error Post 302222708 by kaushikraman on Thursday 7th of August 2008 11:21:43 AM
Old 08-07-2008
I got it now. Thanks anyways..

it must be expr[space]$variable[space]\*[space]60

thanks
 

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s_curl(3rheolef)						    rheolef-6.1 						  s_curl(3rheolef)

NAME
s_curl -- curl-like operator for the Stokes stream function computation SYNOPSIS
form(const space M, const space& V, "s_curl"); DESCRIPTION
Assembly the form associated to the s_curl operator on a finite element space V: / | b(xi,u) = | u.s_curl(xi) dx | / Omega The M and V space may be a either P1 or P2 finite element space. The M space is scalar-valued while the V is vector-valued. See also form(2) and space(2). For cartesian coordinate systems, this form coincide with the usual "curl" one (see curl(3)). In the axisymmetric case: / | (d xi d xi ) b(xi,u) = | (---- ur - ---- uz) r dr dz | (d z d r ) / Omega The b form is denoted as "s_curl", for Stokes stream function computation (see s_grad_grad(3)) as it is closely related to the "curl" oper- ator (see curl(3)), but differs by the r and 1/r factors, as: ( d (r xi) d xi ) curl(xi) = ( (1/r) -------- ; - -----) ( d r d z ) while ( d xi d xi ) s_curl(xi) = ( ---- ; - ---- ) ( d r d z ) Notice also that the differentiation is performed on the xi variable here: b(xi,u)=(s_curl(xi),u) while the "curl" form brings the differ- entiation on the u vector-valued variable: (curl(u),xi), i.e. a transpose formulation. ORIENTATION AND SIGN FIX
The (r,theta,z) coordinate system has positive orientation, thus (z,r,theta) and (z,r) are positive also. But (r,z,theta) and (r,z) are negative : the sign of s_curl is then inverted to obtain the same result as if (z,r) was used. EXAMPLE
The following piece of code build the form associated to the P1 approximation: geo g("square"); space M(g, "P1"); space V(g, "P1", "vector"); form a(M, V, "s_curl"); SEE ALSO
form(2), space(2), curl(3), s_grad_grad(3), curl(3) rheolef-6.1 rheolef-6.1 s_curl(3rheolef)
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