Using the script: (Called replaceit)
#!/bin/ksh
String=$1
Replace=$2
sed -e "s/${orig}/${new}/g" oldfile.txt > newfile.txt
In oldfile.txt, I'm looking for: getenv("Work")
And change it To: /u/web
I execute the script:
replaceit "getenv(\""Work\"")" /u/web
I'm getting sed... (3 Replies)
Hi all,
I need to know way of inserting backward slash before forward slash. My problem is that i need to supply directory path as an argument while invoking cshell script. This argument is further used in script (i.e. sed is used to insert this path in some file). So i need to place \ in front... (2 Replies)
What is the significance of the forward slash(/) while specifying a directory?
cp -av /dir/ /opt/
and
cp -av /dir /opt
Does effectively the same job it seems? (2 Replies)
i need to replace '/' forward slash with \/(backward slash follwed by a forward slash) using sed command when the forward slash occurs as a first character in a file..
Tried something like this but doesn't seem to work.
find $1 -print0 | xargs -0 sed -i -e 's/^\//\\\//g'
Can someone... (19 Replies)
hi
hope somebody can help, there seems to be bit on the net about this, but still cant make it work the way i need.
i have a file live this
mm dd ff /dev/name1
mm dd ff /dev/name2
mm dd ff /dev/name3
mm dd ff /dev/name4
i need to update /dev/name1 etc to /newdev/new/name1 etc
so... (5 Replies)
Hi,
I have a tab delimited file "test.txt" like this:
id1 342 C/T
id2 7453 T/A/-/G/C
id3 531 T/C
id4 756 A/T/G
id5 23 A/G
id6 717 T/A/C
id7 718 C/T/A
And so on, with the possible choices for letters being A,C,T,G.
I would like to exclude from my file all the lines that do not have... (3 Replies)
I have some directories I am trying to sort. When I attempt to sort them and they are in this format, everything works great:
file
/vol/trees10
/vol/trees2
/vol/trees7
cat file |sort -ts -k2 -n
/vol/trees2
/vol/trees7
/vol/trees10
This makes thefiles in the order... (9 Replies)
./split2.sh: line 1: split/ssl/pop3s.txt: No such file or directory
sort: cannot read: split/ssl/pop3s.txt: No such file or directory
Hi there,
I am pulling data from the following source:
ssl/http
ssl/http
ssl/http-alt
ssl/https
ssl/https
ssl/https
ssl/https
ssl/https
ssl/https... (3 Replies)
I have a file abc.txt which has records like
456 /home/fgg/abdc.txt
3567 /home/fdss/vfgb.txt
23 /home/asd/dfght.txt
I WANT TO REMOVE STRING UNTIL 3RD OCCURANCE OF FORWARD SLASH
Output should be like
abdc.txt
vfgb.txt
dfght.txt (5 Replies)
Discussion started by: himanshupant
5 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)