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Top Forums Shell Programming and Scripting Can anyone make this script run faster? Post 302220059 by Annihilannic on Wednesday 30th of July 2008 09:40:31 PM
Old 07-30-2008
Quote:
Originally Posted by shew01
I'd prefer to display just the total size of the files in the current directory (rather than go through the subdirectories like "du" does). Is this possible with awk?
This should do it.

Code:
ls -l | awk 'NF>=5 {tot+=$5}END {printf "%.f\n",tot}'

The NF>=5 is to skip the first line "total nnnn" which reports the number of 512 byte blocks used in the directory.
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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