07-25-2008
Perhaps multiply the number of days difference by 9 (for 9 working hours) and subtract the working hours not included on the first day and last day? Similarly subtract 9 from days which are weekends.
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Is this code good for this purpose?
<?php
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I wrote the day calculator also in bash. I would like to now, that is it good so?
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holidays(4) File Formats holidays(4)
NAME
holidays - prime/nonprime table for the accounting system
SYNOPSIS
/etc/acct/holidays
DESCRIPTION
The /etc/acct/holidays file describes which hours are considered prime time and which days are holidays. Holidays and weekends are con-
sidered non-prime time hours. /etc/acct/holidays is used by the accounting system.
All lines beginning with an "*" are comments.
The /etc/acct/holidays file consists of two sections. The first non-comment line defines the current year and the start time of prime and
non-prime time hours, in the form:
current_year prime_start non_prime_start
The remaining non-comment lines define the holidays in the form:
month/day company_holiday
Of these two fields, only the month/day is actually used by the accounting system programs.
The /etc/acct/holidays file must be updated each year.
EXAMPLES
Example 1: Example of the /etc/acct/holidays file.
The following is an example of the /etc/acct/holidays file:
* Prime/Nonprime Table for the accounting system
*
* Curr Prime Non-Prime
* Year Start Start
*
1991 0830 1800
*
* only the first column (month/day) is significant.
*
* month/day Company Holiday
*
1/1 New Years Day
5/30 Memorial Day
7/4 Indep. Day
9/5 Labor Day
11/24 Thanksgiving Day
11/25 day after Thanksgiving
12/25 Christmas
12/26 day after Christmas
SEE ALSO
acct(1M)
SunOS 5.10 28 Mar 1991 holidays(4)