how to read a var value into array Post: 302218153

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Top Forums Shell Programming and Scripting how to read a var value into array Post 302218153 by BMDan on Thursday 24th of July 2008 02:01:06 PM

07-24-2008

Registered User

I like this a little better than danmero's example, as it actually puts it in an array:

Code:

for i in $(seq 0 $((${#string}-1))); do array[$i]=${string:$i:1}; done

Which produces:

Code:

$ A=147921231432545436547568678679870; for i in $(seq 0 $((${#A}-1))); do array[$i]=${A:$i:1}; done

$ set | grep array
array=([0]="1" [1]="4" [2]="7" [3]="9" [4]="2" [5]="1" [6]="2" [7]="3" [8]="1" [9]="4" [10]="3" [11]="2" [12]="5" [13]="4" [14]="5" [15]="4" [16]="3" [17]="6" [18]="5" [19]="4" [20]="7" [21]="5" [22]="6" [23]="8" [24]="6" [25]="7" [26]="8" [27]="6" [28]="7" [29]="9" [30]="8" [31]="7" [32]="0" [33]="")

Note that this will fail for especially-large strings; just break out of the for and use a while (or a C-style for()) instead.

If that's what you're looking for, you can also create the same effect as danmero's script with sed:

Code:

$ echo 147921231432545436547568678679870 | sed 's/\(.\)/\1 /g'
1 4 7 9 2 1 2 3 1 4 3 2 5 4 5 4 3 6 5 4 7 5 6 8 6 7 8 6 7 9 8 7 0

Last edited by BMDan; 07-24-2008 at 03:09 PM.. Reason: Add sed solution

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