07-22-2008
UNIX Sort question
I was trying to check for the sort of some columns (say 1-10) of particular file. Now, by default, the Unix sort uses as a separator whitespace (e.g. if you have 'foo bar' then it separates it into 'foo' and 'bar' to use as keys)
Now, I know which particular columns I want to use as the sort key, so i circumvent this by using in the -t option some character I know doesn't occur in the file, e.g. "|"
so, my command looks like
cat abc.txt | sort -c -t "|" -k 1.1,1.10
I know that the file is sorted based on the key (chars 1-10). And yet I get the output that the file is not sorted. Any suggestions??
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SORT(1) General Commands Manual SORT(1)
NAME
sort - sort a file of ASCII lines
SYNOPSIS
sort [-bcdfimnru] [-tc] [-o name] [+pos1] [-pos2] file ...
OPTIONS
-b Skip leading blanks when making comparisons
-c Check to see if a file is sorted
-d Dictionary order: ignore punctuation
-f Fold upper case onto lower case
-i Ignore nonASCII characters
-m Merge presorted files
-n Numeric sort order
-o Next argument is output file
-r Reverse the sort order
-t Following character is field separator
-u Unique mode (delete duplicate lines)
EXAMPLES
sort -nr file # Sort keys numerically, reversed
sort +2 -4 file # Sort using fields 2 and 3 as key
sort +2 -t: -o out # Field separator is :
sort +.3 -.6 # Characters 3 through 5 form the key
DESCRIPTION
Sort sorts one or more files. If no files are specified, stdin is sorted. Output is written on standard output, unless -o is specified.
The options +pos1 -pos2 use only fields pos1 up to but not including pos2 as the sort key, where a field is a string of characters delim-
ited by spaces and tabs, unless a different field delimiter is specified with -t. Both pos1 and pos2 have the form m.n where m tells the
number of fields and n tells the number of characters. Either m or n may be omitted.
SEE ALSO
comm(1), grep(1), uniq(1).
SORT(1)