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Top Forums UNIX for Dummies Questions & Answers extracting first 1000 lines containing "home"... Post 302217370 by radoulov on Tuesday 22nd of July 2008 03:47:22 PM
Old 07-22-2008
Quote:
It's possible to extract from a file the first 1000 (for example) lines containing the word "home"? I can use grep to extract all the lines, but i don't know how to save only the first 1000 lines
Yes,
with GNU grep (on Linux or Cygwin for example):

Code:
grep -m1000 home filename

Otherwise with AWK or Perl:

Code:
perl -ne'print if /home/ and ++$c <= 1000' filename

Code:
awk '/home/ && ++c <= 1000' filename

 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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