07-22-2008
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I have,
LIST="a b c d e"
for word in $LIST
do
echo $word
done
would give me
a
b
c
d
e
With the first iteration of the for loop, I get "a" as the result.
Is it possible that I get both "a" and "b" in only the first iteration.
In the next iteration I get "c" and "d" and so on.... (2 Replies)
Discussion started by: run_time_error
2 Replies
2. Programming
Here is my code:
int startingPort = 200;
string tempPort;
stringstream out;
out<<startingPort;
tempPort = out.str(); //tempPort carries startingPort in string format
//convert tempPort to *char - currentPort going to be passed into getaddrinfo()
char currentPort;... (10 Replies)
Discussion started by: f.ben.isaac
10 Replies
3. Shell Programming and Scripting
Hi I'm having difficulty in writing a script with searching a specified word using sed and replaces that word with numbers that is incremented
I tried this:
#!/bin/sh
awk '{ for (i=2010; i<=NF; i++) sed 's/TBA/$i; }' filename.txt > outputfile.txt
but it doesn't work. here is my desired... (1 Reply)
Discussion started by: sexyTrojan
1 Replies
4. Shell Programming and Scripting
echo "Enter Starting id:"
echo ""
read rvst_strt_idxx
echo ""
echo "Enter Closing id:"
echo ""
read rvst_clsn_idxx
FIELD1=$rvst_strt_idxx
FIELD2="USER"
FIELD3="TEST"
FIELD4="12345"
FIELD5="00000"
echo ""
echo "INSERT INTO TABLE( FIELD1, FIELD2, FIELD3, FIELD4,
... (7 Replies)
Discussion started by: ultimatix
7 Replies
5. Programming
Hello,
what is the result of the below, and how does it work?
int i = 5;
cout << i++ * ++i << endl;
cout << i << endl; (12 Replies)
Discussion started by: milhan
12 Replies
6. Shell Programming and Scripting
I'm currently trying to write a ksh or csh script that would change the name of a file found in directories and attach to the name an incrementing three digit number.
I know how to write a script that will go:
000, 001, 002, 003, etc
The twist is I need more increments then allowed by a 3... (11 Replies)
Discussion started by: Rust
11 Replies
7. UNIX for Dummies Questions & Answers
Hi,
want to increment a variable in a for loop like this:
for (( c=$total-1; c>=0; c-- ))
do
if ;
then
maximo=$valores
fi
done
But it gives the error:
No such file or directory
How can i do this only incrementing the c variable?
Thanks (8 Replies)
Discussion started by: limadario
8 Replies
8. Shell Programming and Scripting
Hi All,
I require some help with the below:
I am trying to incriment the ascii value of a letter and then print it.
So basically "a" becomes "b" and "z" becomes "A".
Does anyone have any pointers?
Cheers,
Parks (10 Replies)
Discussion started by: bParks
10 Replies
9. Shell Programming and Scripting
Hello folks.
I am trying to increment my variable names to match a counter that is to be used later on...
Basically, i have a for loop that lists directories (for example TEST_OS DVP_OS PROD_OS ) but this loop is not static, it may contain 3 directory once and the next run 5 directories.
I... (6 Replies)
Discussion started by: Stephan
6 Replies
10. UNIX for Dummies Questions & Answers
I have a date variable like 2012-12-31 ( YYYY -MM -DD ) in flat file and it has to be incremtented by 1 every time i run the script
Example : i tried the below script after data modifcation but this does not seem to work
expr `20121231 +%Y%m%d` + 1
Note : Mine is not a GNU... (4 Replies)
Discussion started by: akshay01987
4 Replies
LEARN ABOUT OSX
net::ldap::control::postread
Net::LDAP::Control::PostRead(3) User Contributed Perl Documentation Net::LDAP::Control::PostRead(3)
NAME
Net::LDAP::Control::PostRead - LDAPv3 Post-Read control object
SYNOPSIS
use Net::LDAP;
use Net::LDAP::Control::PostRead;
use Net::LDAP::Constant qw( LDAP_CONTROL_POSTREAD LDAP_SUCCESS );
$ldap = Net::LDAP->new( "ldap.mydomain.eg" );
$postread = Net::LDAP::Control::PostRead->new( attrs => [ qw/givenName/ ] );
my $mesg = $ldap->modify( "cn=Barbara Jensen, o=University of Michigan, c=US",
replace => { givenName => "Babs" },
control => $postread );
if ($mesg->code eq LDAP_SUCCESS) {
my ($afterwards) = $mesg->control( LDAP_CONTROL_PREREAD );
my $entry = $afterwards ? $afterwards->entry() : undef;
if ($entry) {
print "givenName changed to '" .
join("', '", $entry->get_value(givenName") .
"' to 'Babs'
");
}
}
DESCRIPTION
"Net::LDAP::Control::PostRead" provides an interface for the creation and manipulation of objects that represent the "Post-Read Controls"
as described by RFC 4527.
In modification operations, the "Post-Read request control" indicates to the server that a copy of the modified entry after the update is
to be returned. After the successful completion of the operation, the accompanying "Post-Read response control" allows one to retrieve the
updated value from the servers's response.
One use case of this control may be to obtain values of operational attributes, such as the "entryUUID" and "modifyTimestamp" attributes,
updated by the server as part of the update operation.
CONSTRUCTOR ARGUMENTS
In addition to the constructor arguments described in Net::LDAP::Control the following are provided.
attrs => [ ATTR, ... ]
A list of attributes to be returned in the entry returned in the response control.
If absent, all attributes are returned.
Operational attributes may be included in the list by explicitly asking for them or by using special "+" feature (provided the server
supports this feature).
METHODS
As with Net::LDAP::Control each constructor argument described above is also available as a method on the object which will return the
current value for the attribute if called without an argument, and set a new value for the attribute if called with an argument.
In addition to these methods, the control also supports the following method:
entry ()
Returns the entry from the response control in the response message to the LDAP request that contained the request control.
The result is either a Net::LDAP::Entry object or undefined.
SEE ALSO
Net::LDAP, Net::LDAP::Control, http://www.ietf.org/rfc/rfc4527.txt
AUTHOR
Peter Marschall <peter@adpm.de>
Please report any bugs, or post any suggestions, to the perl-ldap mailing list <perl-ldap@perl.org>
COPYRIGHT
Copyright (c) 2008,2011 Peter Marschall. All rights reserved. This program is free software; you can redistribute it and/or modify it under
the same terms as Perl itself.
perl v5.16.2 2012-09-20 Net::LDAP::Control::PostRead(3)