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Top Forums Shell Programming and Scripting How to evaluate the value read from a file? Post 302216896 by arunsoman80 on Monday 21st of July 2008 11:34:00 AM
Old 07-21-2008
Question How to evaluate the value read from a file?

Hi,

Could someone please help me with how to do the following?

Say I have a flat file test.lst and the content of the file is:
Report Date - `date '+%m%d%Y'`

I'm trying the following

while read myLine
do
echo ${myLine}
done<test.lst

This prints Report Date - `date '+%m%d%Y'`. I want the output as follows Report Date - 07212008. How can i accomplish this? Would eval print work?

regards,
Arun.
 

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GETDATE(1)							   User Commands							GETDATE(1)

NAME
getdate - AME SYNOPSIS
[-dv][-n dec][-f format] [ra dec sys] itype2otype [date and/or time] DESCRIPTION
Convert date and time between various formats [-dv][-n dec][-f format] itype2otype @file itype: nfd=ISOFITS fd=FITS, dt=yyyy.mmdd, hr=hh:mm:ss, deg=dd:mm:ss jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD ep=epoch, epj=Julian epoch, epb=Besselian epoch lt=local time, ut=UT, ts=seconds since 1950-01-01 now=current time, ang=fractional degrees otype: fd=FITS, dt=yyyy.mmdd, jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD hr=hh:mm:ss, deg=dd:mm:ss, ang=fractional degrees ep=epoch, epj=Julian epoch, epb=Besselian epoch ts=seconds since 1950-01-01, tsu=Unix sec, tsi=IRAF sec gst=Greenwich Sidereal Time, lst=Local Sidereal Time @file: First one or two columns are in itype format ra dec sys: Need for Heliocentric conversions -a: Append date to input file, if there is one -d: Print date without time -e: Print output as ET/TDT/TT converting from UT -f: Format for output number (C printf) -h hours: Longitude in hours, west positive -l degrees: Longitude in degrees, west positive -n: Number of decimal places in sec, epoch, JD -t: Print time without date -v: Verbose getdate 3.8.4 June 2012 GETDATE(1)
All times are GMT -4. The time now is 05:36 PM.
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