Hello again.
I'm trying to use BC to calculate some numbers in a shell script.
I want to have the numbers rounded off to 1 decimal place.
for example:
initsize=1566720
zipsize=4733
I'm trying to get the ratio between them. the equation is:
(($initsize-$zipsize)/$initsize)*100
so... (3 Replies)
Hi Guys,
I am generating a statistical report , below is the snippet of the code :
Now, $nSlices stands for the time duration,meaning,the statistics will be displayed for that particular time duration. Trouble is, for certain values of $totalTime (which is the end time - start time ), i... (9 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (0 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (4 Replies)
Hi,
I am currently using tcsh
I am trying to round a decimal number to the ten-thousandths place
For instance:
1.23456 is rounded up towards 1.2346
I am not looking for truncation, but for rounding. Anyone know how to do this with awk or expr?
Thanks (2 Replies)
Dear Experts,
I'm trying to find a way to round a number but in this way:
14367.577 ---> 14000
I used the following to round the number to the closer integer:
echo $var|awk '{print int($1+0.5)}'
and also:
xargs printf "%1.0f"
However, they don't work for my above... (9 Replies)
Hi all of you,
Would be great if you help me with how to round up to whole number from my input values like
2.99996,2.17890,3.00002,-2.3456,-2.7890
o/p should be like 3,2,3,-2,-3
thnks in adv!!!!
regards (3 Replies)
I have a number, which I want to convert into the nearest floating number upto two places after the decimal point.
E.g.
1.2346 will become 1.23
but
1.2356 will become 1.24 .
Similarly
0.009 will be 0.01
and
0.001 will be 0.00 or 0.0 (not 0, wnat to keep the decimal... (1 Reply)
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
Discussion started by: sea
9 Replies
LEARN ABOUT ULTRIX
ceil
floor(3m)floor(3m)Name
floor, ffloor, fabs, ceil, ceil, trunc, ftrunc, fmod, rint - floor, absolute value, ceiling, truncation, floating point remainder and
round-to-nearest functions
Syntax
#include <math.h>
double floor(x)
double x;
float ffloor(x)
float x;
double ceil(x)
double x;
float fceil(x)
float x;
double trunc(x)
double x;
float ftrunc(x)
float x;
double fabs(x)
double x;
double fmod (x, y)
double x, y;
double rint(x)
double x;
Description
The and routines return the largest integer which is not greater than x for double and float data types, respectively.
The and routines return the smallest integer which is not less than x for double and float data types, respectively.
The and routines return the integer (represented as a floating-point number) of x with the fractional bits truncated for double and float
data types respectively.
The routine returns the absolute value |x|.
The routine returns the floating point remainder of the division of x by y: zero if y is zero or if x/y would overflow; otherwise the num-
ber f with the same sign as x, such that x = iy + f for some integer i, and |f| < |y|.
The routine returns the integer (represented as a double precision number) nearest x in the direction of the prevailing rounding mode.
In the default rounding mode, to nearest, is the integer nearest x with the additional stipulation that if |rint(x)-x|=1/2 then is even.
Other rounding modes can make act like or or round towards zero.
Another way to obtain an integer near x is to declare (in C)
double x; int k; k = x;
The C compiler rounds x towards 0 to get the integer k. Also note that, if x is larger than k can accommodate, the value of k and the
presence or absence of an integer overflow are hard to predict.
The routine is in libc.a rather than libm.a.
See Alsoabs(3), ieee(3m), math(3m)
RISC floor(3m)