Sponsored Content
Full Discussion: memset vs calloc
Top Forums UNIX for Advanced & Expert Users memset vs calloc Post 302215481 by shamrock on Wednesday 16th of July 2008 11:54:26 AM
Old 07-16-2008
memset() initializes byte strings to a user supplied value that is restricted to the unsigned char range. It does not allocate any memory.

calloc() allocates memory of any type (char, int, struct) and initializes that storage to zeros.

Both initialize a given storage area [memset() being the more exclusive of the two functions] but only one allocates memory for storage of a particular object type.
 

8 More Discussions You Might Find Interesting

1. Programming

about memset fuction

Dear all, In my code,i am planning to use memset function to re-initialise an array before populating it everytime. Will using memset function be an overload to the program? (3 Replies)
Discussion started by: ranj@chn
3 Replies

2. UNIX for Dummies Questions & Answers

questions in memset

HI all , please find the piece of code below char *t; char *f; char buf; memset(buf,0,50); after that i am assigning memory for (i=0; i<100; i++) { t = buf+(i*6); f = "ARUN"; } my question .. 1) i have run this it is... (7 Replies)
Discussion started by: arunkumar_mca
7 Replies

3. Solaris

application Crashes on memset ?? any suggestions

Hi All, we have an application that is written in 'C' programming to connects to various servers in the organization. The bellow code establish a TCP connection to connect to the remote servers. the application works perfectly ok, but, after some time the entire process get's crashed and... (2 Replies)
Discussion started by: sudharma
2 Replies

4. Programming

C bzero() to memset() issue

Hi guys, my tool works fine in gentoo, ubuntu now im trying to port it to windows but bzero/bcopy I read aren't working on windows and for better portability I should of use memset() so im trying to translate bzero(buffer,256);in printf("MAIL TO"); strcpy(buffer, rcp); ... (4 Replies)
Discussion started by: Jess83
4 Replies

5. Programming

Calloc C++

Hello all, I have a confusion with calloc function : wz. the difference between the following 2 statemnts: char *ptr; char = (char*)calloc(num, sizeof(char)); char = (char*)calloc(num, sizeof(char*)); Am really confused!!!!! ---------- Post updated at 09:32 AM... (1 Reply)
Discussion started by: mind@work
1 Replies

6. Programming

Iterating and calloc questions.

Whilst creating the function readjust_descr I have stumble across what may be a problem or something that might just work. I was hoping someone could look at the code below and tell me if readjust_descr will clear all null pointers from the structure descr_list. struct descr descr_list =... (6 Replies)
Discussion started by: Errigour
6 Replies

7. Programming

calloc fails: 'Cannot allocate memory'

Hi , experts. I work on Linux station (RedHat 5.7), regular user, but have root password. %> uname -a Linux ran1log06 2.6.18-238.1.1.el5 #1 SMP Tue Jan 4 13:32:19 EST 2011 x86_64 x86_64 x86_64 GNU/Linux %> cat /etc/issue Red Hat Enterprise Linux Client release 5.7 (Tikanga) Kernel \r on... (5 Replies)
Discussion started by: baruchgu
5 Replies

8. Emergency UNIX and Linux Support

Memset fails on Solaris

Hi, memset call is failing on solaris for me. I wrote below code and that also fails. Any hints? void *memset(void *dst, int c, size_t n) { if (n) { char *d = dst; do { *d++ = c; } while (--n); } return dst; } (2 Replies)
Discussion started by: skyineyes
2 Replies
explain_calloc_or_die(3)				     Library Functions Manual					  explain_calloc_or_die(3)

NAME
explain_calloc_or_die - Allocate and clear memory and report errors SYNOPSIS
#include <libexplain/calloc.h> void *explain_calloc_or_die(size_t nmemb, size_t size); void *explain_calloc_on_error(size_t nmemb, size_t size); DESCRIPTION
The explain_calloc_or_die function is used to call the calloc(3) system call. On failure an explanation will be printed to stderr, obtained from the explain_calloc(3) function, and then the process terminates by calling exit(EXIT_FAILURE). The explain_calloc_on_error function is used to call the calloc(3) system call. On failure an explanation will be printed to stderr, obtained from the explain_calloc(3) function, but still returns to the caller. nmemb The nmemb, exactly as to be passed to the calloc(3) system call. size The size, exactly as to be passed to the calloc(3) system call. RETURN VALUE
The explain_calloc_or_die function only returns on success, see calloc(3) for more information. On failure, prints an explanation and exits, it does not return. The explain_calloc_on_error function always returns the value return by the wrapped calloc(3) system call. EXAMPLE
The explain_calloc_or_die function is intended to be used in a fashion similar to the following example: void *result = explain_calloc_or_die(nmemb, size); SEE ALSO
calloc(3) Allocate and clear memory explain_calloc(3) explain calloc(3) errors exit(2) terminate the calling process COPYRIGHT
libexplain version 0.52 Copyright (C) 2010 Peter Miller explain_calloc_or_die(3)
All times are GMT -4. The time now is 05:23 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy