hello,
I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops.
if ; then
echo "no such package"
else
echo "similar version found will use pkgrm"
fi
the above code just displays
please let me know... (2 Replies)
:b:hi,
I have a script as given below:
pr_det="1"
if
then
awk ' BEGIN {printf("%23s","session")}' >> report.txt
awk ' BEGIN {printf "\n"} ' >> report.txt
else
awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt
awk ' BEGIN {printf("%101s","no_recs")} '... (1 Reply)
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if ; then
$day=31
fi
2);;
if ; then
if ; then (2 Replies)
Hi ,
I am getting an error when I run the script for checking word "view" in a file . I am using if statement. like this
if
then
VW_VAR=` cat $TN.${ecmdate}.sql1 | grep -i view | awk '{print $3}' | cut -d '.' -f2 `
echo " VW_$VW_VAR "
sed -e... (16 Replies)
hi,
When i try to run the code below, i get the following error
"ksh: syntax error: `(' unexpected"
i am not able to figure it out. Can anyone help me?
Code: (2 Replies)
Hi,
This is my script to catch any oracle errors.
In this, the $sqlerr returns
ORA-01017: invalid username/password; logon denied
when i specify wrong username/password
the if condition is failing. how can i resolve the issue.
the if statement gives error
sqloutput=`sqlplus -s -L... (1 Reply)
Hi
Can you please tell me what is wrong with this line:
if && ]; then
basically i want to check if x = 12 and F (Filename) end with 'g'. But it is throwing syntax error. (7 Replies)
Can anybody tell the correct way to use the following awk pattern check within an if statement?
When I run this command outside of the if statement
cat /tmp/test2.out | awk -v T=$TIME -v G=$GROUP -v C=$CDATE '$0 ~ T && $0 ~ G && $0 ~ C' | grep -i "Starting the group"
I get the following... (0 Replies)
hello all
im new to unix and when i use below script i get an error :
#! /bin/bash
Echo -e "enter the name of the file : \c"
read file_name
if
then
echo "$file_name found"
else
echo "$file_name not found"
fi
running the script i get below error :
$ ./hello (26 Replies)
Discussion started by: Ibrahims1
26 Replies
LEARN ABOUT PHP
mysqli_stmt_error
MYSQLI_STMT_ERROR(3) 1 MYSQLI_STMT_ERROR(3)mysqli_stmt::$error - Returns a string description for last statement error
Object oriented style
SYNOPSIS
string$mysqli_stmt->error ()
DESCRIPTION
Procedural style
string mysqli_stmt_error (mysqli_stmt $stmt)
Returns a string containing the error message for the most recently invoked statement function that can succeed or fail.
PARAMETERS
o $
stmt -Procedural style only: A statement identifier returned by mysqli_stmt_init(3).
RETURN VALUES
A string that describes the error. An empty string if no error occurred.
EXAMPLES
Example #1
Object oriented style
<?php
/* Open a connection */
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s
", mysqli_connect_error());
exit();
}
$mysqli->query("CREATE TABLE myCountry LIKE Country");
$mysqli->query("INSERT INTO myCountry SELECT * FROM Country");
$query = "SELECT Name, Code FROM myCountry ORDER BY Name";
if ($stmt = $mysqli->prepare($query)) {
/* drop table */
$mysqli->query("DROP TABLE myCountry");
/* execute query */
$stmt->execute();
printf("Error: %s.
", $stmt->error);
/* close statement */
$stmt->close();
}
/* close connection */
$mysqli->close();
?>
Example #2
Procedural style
<?php
/* Open a connection */
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s
", mysqli_connect_error());
exit();
}
mysqli_query($link, "CREATE TABLE myCountry LIKE Country");
mysqli_query($link, "INSERT INTO myCountry SELECT * FROM Country");
$query = "SELECT Name, Code FROM myCountry ORDER BY Name";
if ($stmt = mysqli_prepare($link, $query)) {
/* drop table */
mysqli_query($link, "DROP TABLE myCountry");
/* execute query */
mysqli_stmt_execute($stmt);
printf("Error: %s.
", mysqli_stmt_error($stmt));
/* close statement */
mysqli_stmt_close($stmt);
}
/* close connection */
mysqli_close($link);
?>
The above examples will output:
Error: Table 'world.myCountry' doesn't exist.
SEE ALSO mysqli_stmt_errno(3), mysqli_stmt_sqlstate(3).
PHP Documentation Group MYSQLI_STMT_ERROR(3)