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Full Discussion: debug this script
Top Forums Shell Programming and Scripting debug this script Post 302211334 by abhishek27 on Thursday 3rd of July 2008 05:46:53 AM
Old 07-03-2008
Question debug this script

Code:
echo "input time in hhmmss"
read $st
h=`echo $st | cut -c1-2`
min=`echo $st | cut -c3-4`
s=`echo $st | cut -c5-6`
echo "input  time in hhmmss"
read $end
h1=`echo $end | cut -c1-2`
min1=`echo $end | cut -c3-4`
s1=`echo $end | cut -c5-6`
x= `expr  $h /* 60 + $min`
y= `expr  $h1 /* 60 + $min1`
z= `expr  $y - $x`
for i in `seq 1 $z`
do
cat test | grep "$h$min" >> /home/barmecha/file1
$min=`expr $min + 1`
if test [ $min -eq 60 ]
then
$h=`expr $h + 1`
fi
done

this is a script to extract data from a logfile for a particular date and time but gives some err in line no. 11,12,13,14 i guess it has some problem with expr command and seq.

Last edited by radoulov; 07-03-2008 at 06:52 AM.. Reason: please use code tags
 

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expr(1) 						      General Commands Manual							   expr(1)

Name
       expr - evaluate expressions

Syntax
       expr arg...

Description
       The arguments are taken as an expression.  After evaluation, the result is written on the standard output.  Each token of the expression is
       a separate argument.

       The operators and keywords are listed below.  The list is in order of increasing precedence, with equal precedence operators grouped.

       expr | expr	   Yields the first expr if it is neither null nor 0.  Otherwise yields the second expr.

       expr & expr	   Yields the first expr if neither expr is null or 0.	Otherwise yields 0.

       expr relop expr	   The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false.  The  comparison	is
			   numeric if both expr are integers, otherwise lexicographic.

       expr + expr
	    expr - expr
			   Yields addition or subtraction of the arguments.

       expr * expr
	    expr / expr
	    expr % expr
			   Yields multiplication, division, or remainder of the arguments.

       expr : expr	   The	matching  operator compares the string first argument with the regular expression second argument; regular expres-
			   sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the  first  argument.
			   Otherwise, the matching operator yields the number of characters matched ('0' on failure).

       ( expr ) 	   parentheses for grouping.

Examples
       The first example adds 1 to the Shell variable a:
       a=`expr $a + 1`
       The second example finds the file name part (least significant part) of the pathname stored in variable a,
       expr $a : '.*/(.*)' '|' $a
       Note the quoted Shell metacharacters.

Diagnostics
       The command returns the following exit codes:

       0    The expression is neither null nor '0'.

       1    The expression is null or '0'.

       2    The expression is invalid.

See Also
       ed(1), sh(1), test(1)

																	   expr(1)
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