hi all
i want to count the number of files in a particlar dir i have wrote the codes as below
fileCount= ls | wc -l
if
then
echo " "
elif
then
echo " "
fi
however when i excute the program
there are error happens " unary operator expected"
i just woundering
fileCount=... (4 Replies)
I have 1800 files in a directory. The file name is like out_cpty_XXXX. The "XXXX" vaires from file to file. I want to get the count of files with file name out_cpty_XXXX. How to get the count with just the partial file name?
Any help would be appreciated? (4 Replies)
Dear Members,
I want to count the number of lines in a file; for that i am using the following command :
FILE_LINE_COUNT=`wc -l $INT_IN/$RAW_FILE_NAME`
if i do an echo on FILE_LINE_COUNT then i get
241 /home/data/testfile.txt
I don't want the directory path to be displayed. Variable... (1 Reply)
Hi Everyone,
1.txt
Mon 08 Feb 2010 12:30:44 AM MYT;1265560244;e164:0000116047275464;T;Central;0;
Mon 08 Feb 2010 12:30:46 AM MYT;1265560246;e164:0000116047275464;T;Central;0;
Mon 08 Feb 2010 12:30:48 AM MYT;1265560248;e164:0000116047275464;T;Central;0;
Mon 08 Feb 2010 12:30:50 AM... (1 Reply)
Hi!
I just want to count number of files in a directory, and write to new text file, with number of files and their name
output should look like this,,
assume that below one is a new file created by script
Number of files in directory = 25
1. a.txt
2. abc.txt
3. asd.dat... (20 Replies)
Hi,
I have a requirement where in I need to insert delimiters before the last column of the total delimiters is less than a specified number.
Say if the delimiters is less than 139, I need to insert 2 columns ( with blanks) before the last field
awk -F 'Ç' '{ if (NF-1 < 139)} END { "Insert 2... (5 Replies)
Hi All,
I'm stuck-up in finding a way to skip the delimiter which come within double quotes using awk or any other better option. can someone please help me out.
Below are the details:
Delimited: |
Sample data: 742433154|"SYN|THESIS MED CHEM PTY.... (2 Replies)
What to know the way to count the number of delimiters in each record by ignoring the escape delimiters.
Sample Data:
12345678|ABN\|XYZ MED CHEM PTY. LTD.|C||100.00|22|AB"C\|Corp|"XYZ|CDEF"|
I'm using awk -F'|' '{ print NF-1 }' command to find the number of delimiters. this command... (8 Replies)
Discussion started by: BrahmaNaiduA
8 Replies
LEARN ABOUT SUNOS
print
print(1) User Commands print(1)NAME
print - shell built-in function to output characters to the screen or window
SYNOPSIS
ksh
print [ -Rnprsu [n]] [arg...]
DESCRIPTION
ksh
The shell output mechanism. With no flags or with flag - or -, the arguments are printed on standard output as described by echo(1).
OPTIONS
The following options are supported:
-n suppresses new-line from being added to the output.
-R
-r (raw mode) ignore the escape conventions of echo. The -R option will print all subsequent arguments and options other than
-n.
-p causes the arguments to be written onto the pipe of the process spawned with |& instead of standard output.
-s causes the arguments to be written onto the history file instead of standard output.
-u [ n ] flag can be used to specify a one digit file descriptor unit number n on which the output will be placed. The default is 1.
EXIT STATUS
The following exit values are returned:
0 Successful operation.
>0 Output file is not open for writing.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO echo(1), ksh(1), attributes(5)SunOS 5.10 15 Apr 1994 print(1)