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Top Forums UNIX for Dummies Questions & Answers How to count number of delimiters in a file name Post 302209497 by Franklin52 on Friday 27th of June 2008 06:41:39 AM
Old 06-27-2008
Or:

Code:
number=$(echo $var|awk -F_ '{print NF-1}')

Regards
 

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print(1)							   User Commands							  print(1)

NAME
print - shell built-in function to output characters to the screen or window SYNOPSIS
ksh print [ -Rnprsu [n]] [arg...] DESCRIPTION
ksh The shell output mechanism. With no flags or with flag - or -, the arguments are printed on standard output as described by echo(1). OPTIONS
The following options are supported: -n suppresses new-line from being added to the output. -R -r (raw mode) ignore the escape conventions of echo. The -R option will print all subsequent arguments and options other than -n. -p causes the arguments to be written onto the pipe of the process spawned with |& instead of standard output. -s causes the arguments to be written onto the history file instead of standard output. -u [ n ] flag can be used to specify a one digit file descriptor unit number n on which the output will be placed. The default is 1. EXIT STATUS
The following exit values are returned: 0 Successful operation. >0 Output file is not open for writing. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
echo(1), ksh(1), attributes(5) SunOS 5.10 15 Apr 1994 print(1)
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