Sponsored Content
Top Forums Shell Programming and Scripting extraction of perfect text from file. Post 302207544 by nua7 on Friday 20th of June 2008 08:04:27 AM
Old 06-20-2008
Data Please help!

Guys, please help!

I basically want to replace the plain text passwd with the encrypted passwd.

I get the encrypted passwd using the script: /opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha $i

Please let me know the right command for this. I am goofing up the perl command somewhere.

Thanks!
nua7
 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Shell script for text extraction from a file

Hi All, I am new to Shell Scripting. I have a file consisting of XML messages.Each message is associated with a timestamp value(it is not a xml field).I need to extract\copy all messages in a particular time interval and put in another new file using Shell Scripting. My XML looks like... (3 Replies)
Discussion started by: vignesh53
3 Replies

2. UNIX for Advanced & Expert Users

extraction of data from a text file which follows certain pattern

hi everybody, i have a file, in it I need to extract some data that follows a particular pattern.. For example: my file contains like now running Speak225 sep 22 mon 16:34:05 2008 -------------------------------- ... (4 Replies)
Discussion started by: mohkris
4 Replies

3. UNIX for Dummies Questions & Answers

String extraction from a text file

The following script code works great for extracting 'postmaster' from a line of text stored in a variable named string: string="PenaltyError:=554 5.7.1 Error, send your mail to postmaster@LOCALDOMAIN" stuff=$( echo $string | cut -d@ -f1 | awk '{ print $NF }' ) echo $stuff However, I need to be... (9 Replies)
Discussion started by: cleanden
9 Replies

4. Shell Programming and Scripting

Extraction of data from multiple text files, and creation of a chart

Hello dear friends, My problem as explained below seems really basic. Fact is that I'm totally new to programming, and have only a week to produce a script ( CShell or Perl ? ) to perform this action. While searching on the forums, I found a command that could help me, but I don't know... (2 Replies)
Discussion started by: ackheron
2 Replies

5. Shell Programming and Scripting

Extraction of text using sed or awk command

Hi All, I need to extract 543 from the command below : # pvscan PV /dev/sdb1 VG vg0 lvm2 Total: 1 543.88 GB] / in use: 1 / in no VG: 0 I have the following command which does the job, but I think this could be achieved in a more simple way using sed or awk. Any help is... (7 Replies)
Discussion started by: nua7
7 Replies

6. Shell Programming and Scripting

awk - horizontal and vertical text extraction

Hi, I need some help in getting extracting the specific horizontal and vertical texts in a single line. I am trying to extract few of the parameters from a config file. Your help is appreciated. Desired Output ---------------- Pool members members ... (4 Replies)
Discussion started by: pratheeshp
4 Replies

7. Shell Programming and Scripting

sed text extraction between 2 patterns using variables

Hi everyone! I'm writting a function in .bashrc to extract some text from a file. The file looks like this: " random text Begin CG step 1 random text Begin CG step 2 ... Begin CG step 100 random text" For a given number, let's say 70, I want all the text between "Begin CG... (4 Replies)
Discussion started by: radudownload
4 Replies

8. Shell Programming and Scripting

Text extraction

Dear All, I am trying to extract text from a file containing cron entries. cat /var/tmp/cron_backups/debmed_tmp < * * * * * /bell > * * * * * /belly what I am trying to do is create two text files containing all entries that begin with < and another text files containing entries with > .... (4 Replies)
Discussion started by: Junaid Subhani
4 Replies

9. Shell Programming and Scripting

Solution which is works perfect if all headers match from file b

HI Guys, I have file A.txt Code: ID,L1,L2,L3,L4 1A,2a,33a,44b,55c 2A,10a,14a,15b,16c File B.txt Code: ID L1 L4 L5 Output:- Code: (3 Replies)
Discussion started by: huuanh2811
3 Replies
d_passwd(4)							   File Formats 						       d_passwd(4)

NAME
d_passwd - dial-up password file SYNOPSIS
/etc/d_passwd DESCRIPTION
A dial-up password is an additional password required of users who access the computer through a modem or dial-up port. The correct pass- word must be entered before the user is granted access to the computer. d_passwd is an ASCII file which contains a list of executable programs (typically shells) that require a dial-up password and the associ- ated encrypted passwords. When a user attempts to log in on any of the ports listed in the dialups file (see dialups(4)), the login program looks at the user's login entry stored in the passwd file (see passwd(4)), and compares the login shell field to the entries in d_passwd. These entries determine whether the user will be required to supply a dial-up password. Each entry in d_passwd is a single line of the form: login-shell:password: where login-shell The name of the login program that will require an additional dial-up password. password An encrypted password. Users accessing the computer through a dial-up port or modem using login-shell will be required to enter this password before gaining access to the computer. d_passwd should be owned by the root user and the root group. The file should have read and write permissions for the owner (root) only. If the user's login program in the passwd file is not found in d_passwd or if the login shell field in passwd is empty, the user must sup- ply the default password. The default password is the entry for /usr/bin/sh. If d_passwd has no entry for /usr/bin/sh, then those users whose login shell field in passwd is empty or does not match any entry in d_passwd will not be prompted for a dial-up password. Dial-up logins are disabled if d_passwd has only the following entry: /usr/bin/sh:*: EXAMPLES
Example 1: Sample d_passwd file. Here is a sample d_passwd file: /usr/lib/uucp/uucico:q.mJzTnu8icF0: /usr/bin/csh:6k/7KCFRPNVXg: /usr/bin/ksh:9df/FDf.4jkRt: /usr/bin/sh:41FuGVzGcDJlw: Generating An Encrypted Password The passwd (see passwd(1)) utility can be used to generate the encrypted password for each login program. passwd generates encrypted pass- words for users and places the password in the shadow (see shadow(4)) file. Passwords for the d_passwd file will need to be generated by first adding a temporary user id using useradd (see useradd(1M)), and then using passwd(1) to generate the desired password in the shadow file. Once the encrypted version of the password has been created, it can be copied to the d_passwd file. For example: 1. Type useradd tempuser and press Return. This creates a user named tempuser. 2. Type passwd tempuser and press Return. This creates an encrypted password for tempuser and places it in the shadow file. 3. Find the entry for tempuser in the shadow file and copy the encrypted password to the desired entry in the d_passwd file. 4. Type userdel tempuser and press Return to delete tempuser. These steps must be executed as the root user. FILES
/etc/d_passwd dial-up password file /etc/dialups list of dial-up ports requiring dial-up passwords /etc/passwd password file /etc/shadow shadow password file SEE ALSO
passwd(1), useradd(1M), dialups(4), passwd(4), shadow(4) WARNINGS
When creating a new dial-up password, be sure to remain logged in on at least one terminal while testing the new password. This ensures that there is an available terminal from which you can correct any mistakes that were made when the new password was added. SunOS 5.10 2 Sep 2004 d_passwd(4)
All times are GMT -4. The time now is 05:07 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy