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Top Forums Shell Programming and Scripting Split a file based on pattern in awk, grep, sed or perl Post 302207477 by Franklin52 on Friday 20th of June 2008 04:02:55 AM
Old 06-20-2008
Quote:
Originally Posted by ripat
With (g)awk

Code:
awk 'BEGIN{RS="\n?B"} (NR-1){print "B" $0 > ("output-file_" NR)}' input-file

Ripat, your solution doesn't give the desired output...

Try this:

Code:
awk '/^B/{close("file"f);f++}{print $0 > "file"f}' file

Regards
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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