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Top Forums Shell Programming and Scripting Variable problem in for loop with if statement Post 302206192 by ejdv on Tuesday 17th of June 2008 07:40:39 AM
Old 06-17-2008
MySQL

Quote:
Originally Posted by ynir
You just need to wrap items in double quotes.
Better to use also curly brackets:
[/CODE]
Thanks, that works wonders.
Are you able to explain what is does exactly ?

Just because $ITEM, ${ITEM} and "${ITEM}" give the same value for the variable.
And I would like to learn from it :-)

ejdv
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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