06-17-2008
option of grep for counting exact word ??
Hi All,
I have a quary regarding grep command in linux.
I have a file which contains
56677
56677
+56677
+56677
56677
56677
56677
I want to extract total count of "56677"
When I hit the following command
#cat filename | grep -w -c '56677'
the result comes 7. Its counting including "+56677". I need count of only "56677" .
Is there any option of grep to extract count of only "56677" excluding count of "+56677".
Please provide the command ASAP.
Waiting for the response ...
Thanks in advance ..
Maddy
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GREP(1) General Commands Manual GREP(1)
NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS
-e -e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)