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Top Forums Shell Programming and Scripting To find all common lines from 'n' no. of files Post 302204998 by The Observer on Friday 13th of June 2008 06:01:25 AM
Old 06-13-2008
Sorry Sir,
My requirement is I want the lines which are present in all these 'n' files. Means every line which will come in output must be present in each of these 'n' files.

Please guide.

Last edited by The Observer; 06-13-2008 at 07:07 AM..
 

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bdiff(1)						      General Commands Manual							  bdiff(1)

Name
       bdiff - big file differential comparator

Syntax
       bdiff file1 file2 [n] [-s]

Description
       The  command  is  used to find lines that must be changed in two files to bring them into agreement.  Its purpose is to allow processing of
       files that are too large for

       The command ignores lines common to the beginning of both files, splits the remainder of each file into n-line segments, and  invokes  upon
       corresponding  segments.   The  value of n is 3500 by default.  If the optional third argument is given and if it is numeric, it is used as
       the value for n.  This is useful in those cases in which 3500-line segments are too large for causing it to fail.

       The output of the command is the same as the output of the command: line numbers are adjusted to account for the segmenting of the files to
       make  it  look  as  if the files had been processed whole.  Note that because of the segmenting of the files, does not necessarily find the
       smallest sufficient set of file differences.

       If either file1 or file2 is -, the standard input is read.  The optional -s (silent) argument specifies	that  no  diagnostics  are  to	be
       printed by However, this does not suppress possible exclamations by If both optional arguments are specified, they must appear in the order
       indicated above.

Options
       -s		   Suppresses normal diagnostic messages.

Diagnostics
       Use for explanations.

Files
       /tmp/bd?????

See Also
       diff(1)

																	  bdiff(1)
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