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Full Discussion: changing modified time
Top Forums Shell Programming and Scripting changing modified time Post 302204607 by ali560045 on Thursday 12th of June 2008 05:47:30 AM
Old 06-12-2008
changing modified time

How to change the modified time of a file to any specified time.

ls -ltr

drwxr-xr-x 2 pipe pipe 4096 Jun 10 10:33 coredump_06062008
----------------------------------------------------------------------
here file coredump_06062008 last modified time is Jun 10 10:33 and i want to change it to Jun 10.
 

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PIPE(2) 							System Calls Manual							   PIPE(2)

NAME
pipe - create an interprocess communication channel SYNOPSIS
#include <unistd.h> int pipe(int fildes[2]) DESCRIPTION
The pipe system call creates an I/O mechanism called a pipe. The file descriptors returned can be used in read and write operations. When the pipe is written using the descriptor fildes[1] up to PIPE_MAX bytes of data are buffered before the writing process is suspended. A read using the descriptor fildes[0] will pick up the data. PIPE_MAX equals 7168 under Minix, but note that most systems use 4096. It is assumed that after the pipe has been set up, two (or more) cooperating processes (created by subsequent fork calls) will pass data through the pipe with read and write calls. The shell has a syntax to set up a linear array of processes connected by pipes. Read calls on an empty pipe (no buffered data) with only one end (all write file descriptors closed) returns an end-of-file. The signal SIGPIPE is generated if a write on a pipe with only one end is attempted. RETURN VALUE
The function value zero is returned if the pipe was created; -1 if an error occurred. ERRORS
The pipe call will fail if: [EMFILE] Too many descriptors are active. [ENFILE] The system file table is full. [ENOSPC] The pipe file system (usually the root file system) has no free inodes. [EFAULT] The fildes buffer is in an invalid area of the process's address space. SEE ALSO
sh(1), read(2), write(2), fork(2). NOTES
Writes may return ENOSPC errors if no pipe data can be buffered, because the pipe file system is full. BUGS
Should more than PIPE_MAX bytes be necessary in any pipe among a loop of processes, deadlock will occur. 4th Berkeley Distribution August 26, 1985 PIPE(2)
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