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Top Forums Shell Programming and Scripting Ascending & Descending order numbers Post 302201714 by era on Tuesday 3rd of June 2008 02:20:02 AM
Old 06-03-2008
Actually the cat is useless, and you can use sort -u to avoid the uniq. You probably want numeric sort anyway.

Code:
sort -nu file | tail -n 3

Your example suggests you want the last three numbers (i.e. simply tail -n 3 file), not the sorted output. The last three numbers from an ascending sort would be 382, 432, and 433 from the sample input you provided.
 

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SORT(1) 						      General Commands Manual							   SORT(1)

NAME
sort - sort a file of ASCII lines SYNOPSIS
sort [-bcdfimnru] [-tc] [-o name] [+pos1] [-pos2] file ... OPTIONS
-b Skip leading blanks when making comparisons -c Check to see if a file is sorted -d Dictionary order: ignore punctuation -f Fold upper case onto lower case -i Ignore nonASCII characters -m Merge presorted files -n Numeric sort order -o Next argument is output file -r Reverse the sort order -t Following character is field separator -u Unique mode (delete duplicate lines) EXAMPLES
sort -nr file # Sort keys numerically, reversed sort +2 -4 file # Sort using fields 2 and 3 as key sort +2 -t: -o out # Field separator is : sort +.3 -.6 # Characters 3 through 5 form the key DESCRIPTION
Sort sorts one or more files. If no files are specified, stdin is sorted. Output is written on standard output, unless -o is specified. The options +pos1 -pos2 use only fields pos1 up to but not including pos2 as the sort key, where a field is a string of characters delim- ited by spaces and tabs, unless a different field delimiter is specified with -t. Both pos1 and pos2 have the form m.n where m tells the number of fields and n tells the number of characters. Either m or n may be omitted. SEE ALSO
comm(1), grep(1), uniq(1). SORT(1)
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