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Top Forums Shell Programming and Scripting find the length of file names in a directory? Post 302201414 by Yogesh Sawant on Monday 2nd of June 2008 07:27:23 AM
Old 06-02-2008
using bash:
Code:
for file in *
do
    ff=`echo $file | cut -d '.' -f1`
    echo -n "$ff "
    echo ${#ff}
done

 

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list directory(1m)														list directory(1m)

NAME
list directory - Displays a list of all the directories whose names match the specified directory name SYNOPSIS
cdscp list directory directory-name [with attribute-name = attribute-value] ARGUMENTS
The full name of a specific directory. The last simple name can contain wildcard characters. The name of a particular attribute. The value of a particular attribute. DESCRIPTION
The list directory command displays a list of all the directories whose names match the specified directory name. The last simple name can contain wildcards. You can use a with attribute-name = attribute-value clause to limit output only to directories whose attributes have values equal to the specified values. A space must precede and follow the = (equals sign). Privilege Required You must have read permission to the parent directory. If you use a with attribute-name = attribute-value clause in the command, you also need read or test permission to the selected directories. NOTE
This command is replaced at Revision 1.1 by the dcecp command and may not be provided in future releases of DCE. EXAMPLE
The following command displays the names of all the directories in the /.:/sales directory: cdscp> list directory /.:/sales/* LIST DIRECTORY /.../abc.com/sales AT 1991-10-15-15:43:58 atlanta austin boston chicago ontario ny seattle RELATED INFORMATION
Commands: add directory(1m), create directory(1m), delete directory(1m), remove directory(1m), set directory(1m), set directory to skulk(1m), show directory(1m) list directory(1m)
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