My scripts excepts 4 files
ABCD_01
ABCD_02
ABCD_03
ABCD_04
I want to check for these files , and increment counter one by one .
at the end i would like to echo as 4 of 4 expected instances of file found .
I tried something like thsi
$counter =1
if
counter=counter+1
i need... (5 Replies)
count=0;
while read line;
do ] && let count=count+1; done < file_name.txt
echo
echo "$count of 10 files found "
echo
The scenario is a follows :
I have a file which contains a list of filenames present in particular directory .
I am checking fo the existence of the file and... (5 Replies)
Experts,
I would appreciate if someone took the time to express there opinion /approach in creating a new change daily to a configuration file. I create a new log file each day and I wish to have a browser based reader display the new file. To achieve this I would need to create a new... (2 Replies)
Hi
I have the file called "file.txt" which contains the following output
$cat file.txt
sandy
<version>1</version>
karen
<version>2</version>
Rob
<version>3</version>
peter
<version>4</version>
i want to write a command which will add the value 1 to the digits and show the output... (2 Replies)
Hi Experts,
I am writing a shell script (for displaying disk space details) which is logging to 15 different servers using following command.
ssh userid@servername
It is prompting me for password for all 15 servers when I manually run it.
However , soon I would like to schedule this script... (4 Replies)
Hello,
I have a text file withe some records
20121031|5
20121030|3
20121029|1
20121028|4
20121027|6
I want to search for a patten with '20121030' and then increment the second part of the delimiter i.e. 3 by 1 to make it 4 to look like
20121031|5
20121030|4
20121029|1
20121028|4... (7 Replies)
Hi Guys,
I am new to shell programing, I have a csv file which has 50k records and I have got the requirement to increment the value in second column after each 5000 records.
for example below
A,B,C,D //Header
1,1,London,UK
1,1,Manchester,UK
1,1,Glasgow,UK
.
.
.
1,1,Newyork,USA... (7 Replies)
Hello,
I have a few thousand .pdf files in various folders each have a naming scheme like this:
006_-_Titled_Document_#34_-_September-25-2011-side-1.pdf
In each folder, the number system starts at 001 (as you see on the far left of the file name), and then ends at 999 (maximum .pdf files).... (4 Replies)
Hi All,
I need to write a shell script which opens a file and increments the version(text) within the file every time the script runs. For example:
$ cat docker_file.yml
version: '3.1'
services:
ui:
image: repo-srv.dev.io:5000/facebook/ui:0.0.2-QA1
$
So, I would like... (6 Replies)
Discussion started by: akshayupadhayay
6 Replies
LEARN ABOUT V7
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO ed(1), sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
EXPR(1)