05-22-2008
OK, do a 'grep "time stamp here" file-name > filteredLogs.tmp; cp filteredLogs.tmp whateverNameYouLike.log and voila
The grep for particular pattern will output the lines matching the criteria, and then you redirect the result to a temp file, then you copy this file with a preferred name, HTH.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I am sorry to repost this question. it was not clear, and I had the meeting and didn't response the question on time. I do really need help and appreciate your help very much.
I'm looking for a simple shell script that will read lots of audit log file (*.aud) in a log fold every 10 minutes,... (1 Reply)
Discussion started by: percvs88
1 Replies
2. Shell Programming and Scripting
I'm looking for a command or simple script that will read lots of audit log file (*.aud) in log fold every 10 minutes, and will output to one file based on sysdate - 10 minutes. assume the script is run at 11:12:20, and it
should grep the line from Wed Jun 17 11:02:43 2009 to end of file. after... (4 Replies)
Discussion started by: percvs88
4 Replies
3. Shell Programming and Scripting
Hi,
Using sed awk or perl I am trying to do something similar to
https://www.unix.com/shell-programming-scripting/105887-sed-awk-concatenate-lines-until-blank-line-2.html
but my requirement is slightly different. What I am trying to accomplish is to reformat a logfile such that all lines... (4 Replies)
Discussion started by: AlanC
4 Replies
4. Shell Programming and Scripting
Hello everyone. I have a log file that contains multiple domains:
www.thisdomain.com
agent.thisdomain.com
that.thisdomain.com
I need to copy all of the lines that contain "www.thisdomain.com" from the log and output them into a new file. I've tried everything with little luck. Please help... (3 Replies)
Discussion started by: aberli
3 Replies
5. Shell Programming and Scripting
If a log file is in the following format
28-Jul-10 ::: Log message
28-Jul-10 ::: Log message
29-Jul-10 ::: Log message
30-Jul-10 ::: Log message
31-Jul-10 ::: Log message
31-Jul-10 ::: Log message
1-Aug-10 ::: Log message
1-Aug-10 ::: Log message
2-Aug-10 ::: Log message
2-Aug-10 :::... (3 Replies)
Discussion started by: vikram3.r
3 Replies
6. Shell Programming and Scripting
Dear friends..
I have the below listing of files under a directory in unix
-rw-r--r-- 1 abc abc 263349631 Jun 1 11:18 CDLD_20110603032055.xml
-rw-r--r-- 1 abc abc 267918241 Jun 1 11:21 CDLD_20110603032104.xml
-rw-r--r-- 1 abc abc 257672513 Jun 3 10:41... (5 Replies)
Discussion started by: sureshg_sampat
5 Replies
7. Shell Programming and Scripting
Hi Guys,
I have the following problem. I have original file (org.txt) that looks like this
module v_1(.....)
//arbitrary number of text lines
endmodule
module v_2(....)
//arbitrary number of text lines
endmodule
module v_3(...)
//arbitrary number of text lines
endmodule
module... (6 Replies)
Discussion started by: kaaliakahn
6 Replies
8. Shell Programming and Scripting
hi
i have an input file that contains some thing like this
aaa acc aa abc1 1232 aaa abc2....
poo awq aa abc1 aaa aaa abc2
bbb bcc bb abc1 3214 bbb abc3....
bab bbc bz abc1 3214 bbb abc3....
vvv ssa as abc1 o09 aaa abc4....
azx aaq aa abc1 900 aqq abc19....
aaa aa aaaa abc1 899 aa... (8 Replies)
Discussion started by: anurupa777
8 Replies
9. Shell Programming and Scripting
I was looking at this script which outputs the two lines which differs less than one sec.
#!/usr/bin/perl -w
use strict;
use warnings;
use Time::Local;
use constant SEC_MILIC => 1000;
my $file='infile';
## Open for reading argument file.
open my $fh, "<", $file or die "Cannot... (1 Reply)
Discussion started by: cele_82
1 Replies
10. UNIX for Beginners Questions & Answers
Dear Experts,
I have a log file that contains a timestamp, I would like to filter record from that file based on timestamp. For example refer below file -
cat sample.txt
Jan 19 20:51:48 mukul-Vostro-14-3468 systemd: pam_unix(systemd-user:session): session opened for user root by (uid=0)... (6 Replies)
Discussion started by: mukulverma2408
6 Replies
LEARN ABOUT SUSE
grep-changelog
grep-changelog(1) General Commands Manual grep-changelog(1)
NAME
grep-changelog - print ChangeLog entries matching criteria
SYNOPSIS
grep-changelog [options] [CHANGELOG...]
DESCRIPTION
grep-changelog searches the named CHANGELOGs (by default files matching the regular expressions ChangeLog and ChangeLog.[0-9]+) for
entries matching the specified criteria. At least one option or file must be specified. This program is distributed with GNU Emacs.
OPTIONS
The program accepts unambiguous abbreviations for option names.
--author=AUTHOR
Print entries whose author matches regular expression AUTHOR.
--text=TEXT
Print entries whose text matches regular expression TEXT.
--exclude=TEXT
Exclude entries matching regular expression TEXT.
--from-date=YYYY-MM-DD
Only consider entries made on or after the given date. ChangeLog date entries not in the "YYYY-MM-DD" format are never matched.
--to-date=YYYY-MM-DD
Only consider entries made on or before the given date.
--rcs-log
Print output in a format suitable for RCS log entries. This format removes author lines, leading spaces, and file names.
--with-date
In RCS log format, print short dates.
--reverse
Show matches in reverse order.
--version
Display version information.
--help Display basic usage information.
COPYING
Copyright (C) 2008, 2009 Free Software Foundation, Inc.
Permission is granted to make and distribute verbatim copies of this document provided the copyright notice and this permission notice are
preserved on all copies.
Permission is granted to copy and distribute modified versions of this document under the conditions for verbatim copying, provided that
the entire resulting derived work is distributed under the terms of a permission notice identical to this one.
Permission is granted to copy and distribute translations of this document into another language, under the above conditions for modified
versions, except that this permission notice may be stated in a translation approved by the Free Software Foundation.
grep-changelog(1)