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Top Forums Shell Programming and Scripting sort files by date, delete oldest, if total size bigger than Post 302197494 by adhit on Wednesday 21st of May 2008 05:02:18 AM
Old 05-21-2008
Hi Try this one

bdf|awk '{print $5" "$6}'| while read output;
> do
> sizes=$(echo $output|awk '{print $1}'|awk -F "%" '{print $1}')
> dir=$(echo $output|awk '{print $2}')
> if [ $sizes -ge 90 ]; then
> echo "$dir:$sizes"
> ls -lrt $dir |tail -5
> fi
> done

it is listed any dir which has size greater than 90% and short the latest 5 files in those directory, you may modified it so it will suit with you
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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