05-21-2008
Please help to modify my script
Hi,
I have a script which connect to ATM's and pull two files from the ATM.
The which i try to pull is like
PIC20085200001*.JPG
First 7 digit consist of year montn and date as well
After todays execution i want to change the date to next date
I add few lines in the script but it is not working. The lines i added are
FILENAME1="PIC20085200001*.JPG"
DATES='date +%Y%m%d'
FILENAME="PIC_$DATES0001*.JPG"
FILENAME1=$FILENAME
echo $FILENAME1
Please help me to fix this
Thanks in advance
Renjesh
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LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)
DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)