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Full Discussion: How to pass variable variable
Top Forums Shell Programming and Scripting How to pass variable variable Post 302197331 by primp on Tuesday 20th of May 2008 08:45:14 PM
Old 05-20-2008
You've sort of answered you question, you substituted $1 which is the first command line argument to executing your script.

i.e.
# ./myscript.sh option1

$1 = option1

To verify you an do something like:

Code:
#!/bin/sh
#test_commandline_args.sh

echo $1

Now you should definitely create just 1 script across your 3 different environments, this can be done in many ways, you can query the hostname of the system if it can designate which is PROD/TEST/DEV or you can do what you had mentioned, which was to accept command line arguments. You can also do some checking to verify that its only one of the 3 options and error on any other input.

i.e.
Code:
#!/bin/sh
# myscript.sh

if [ $# != 1 ]; then
        echo "Usage: $0 [option]"
        echo "Option: PROD, TEST, DEV"
        echo -e "\ti.e. - $0 PROD\n"
        exit 1
fi

case $1 in
        PROD|prod)
                        ENV="PROD"
                        ;;
        TEST|test)
                        ENV="TEST"
                        ;;
        DEV|dev)
                        ENV="DEV"
                        ;;
                *)
                        echo "Usage: $0 [option]"
                        echo "Option: PROD, TEST, DEV"
                        ;;
esac

## use variable "ENV" to pass into the directory structure ##
echo $ENV

This should help, there's more than one way to do this but here's an option
 

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