In ksh shell,
There is a function f1.
function f1
{
How to read here??
....
....
}
I am passing values to fuunction f1 as
f1 "A" "B"
Please tell me how to read the passed values in function f1.
Advance Thanks & Regards
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FORWARD_STATIC_CALL_ARRAY(3) 1 FORWARD_STATIC_CALL_ARRAY(3)forward_static_call_array - Call a static method and pass the arguments as arraySYNOPSIS
mixed forward_static_call_array (callable $function, array $parameters)
DESCRIPTION
Calls a user defined function or method given by the $function parameter. This function must be called within a method context, it can't
be used outside a class. It uses the late static binding. All arguments of the forwarded method are passed as values, and as an array, sim-
ilarly to call_user_func_array(3).
PARAMETERS
o $function
- The function or method to be called. This parameter may be an array, with the name of the class, and the method, or a string,
with a function name.
o $parameter
- One parameter, gathering all the method parameter in one array.
Note
Note that the parameters for forward_static_call_array(3) are not passed by reference.
RETURN VALUES
Returns the function result, or FALSE on error.
EXAMPLES
Example #1
forward_static_call_array(3) example
<?php
class A
{
const NAME = 'A';
public static function test() {
$args = func_get_args();
echo static::NAME, " ".join(',', $args)."
";
}
}
class B extends A
{
const NAME = 'B';
public static function test() {
echo self::NAME, "
";
forward_static_call_array(array('A', 'test'), array('more', 'args'));
forward_static_call_array( 'test', array('other', 'args'));
}
}
B::test('foo');
function test() {
$args = func_get_args();
echo "C ".join(',', $args)."
";
}
?>
The above example will output:
B
B more,args
C other,args
SEE ALSO forward_static_call(3), call_user_func(3), call_user_func_array(3), is_callable(3), information about the callback type.
PHP Documentation Group FORWARD_STATIC_CALL_ARRAY(3)