05-19-2008
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
Discussion started by: rameshspal
1 Replies
2. Shell Programming and Scripting
Hello Unix gurus,
I need to add days to the input date and further use it in comparision with the existing date.
Im having issues sto add days to date,can you guys help me with script or function with which I can add days to the date.
Thanks,
Sud (10 Replies)
Discussion started by: sud
10 Replies
3. Windows & DOS: Issues & Discussions
Hi,
I'm writing an batch file to create report
In the batch file iam passing two arguments:startdate and finishdate
Ex: startdate=07-sep-2009 finishdate=07-sep-2011
I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Discussion started by: anand1773
2 Replies
4. Shell Programming and Scripting
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Discussion started by: kokoro
1 Replies
5. UNIX for Dummies Questions & Answers
Hi Gurus!
I have a static date in a YYYYMMDD format; and I want get the date 2 years in the past and 2 years in the future.
static_date=20010203
old_date=$static_date - 3 years
future_date=$static_date + 2 years
I was only able to research on dates that are current and not on static... (3 Replies)
Discussion started by: kokoro
3 Replies
6. Shell Programming and Scripting
Hi ,
How can I add/substruct x number of days with date?
For example
My_Date=`date`
Now I need
Hope it's clear. (2 Replies)
Discussion started by: Anupam_Halder
2 Replies
7. UNIX for Dummies Questions & Answers
Hi All,
I am using KSH shell and need to subtract n number of days from the current date .. kindly suggest !
Thanks in advance!:) (20 Replies)
Discussion started by: dev.devil.1983
20 Replies
8. Shell Programming and Scripting
Hi, please can somebody let me know the easiest way to add days to a date.
I can do this in perl but would like to able to do it in a shell script.
Desired output would be:
date +'%Y-%m-%d' + 10 = 2016-05-02
Thank you (8 Replies)
Discussion started by: andy391791
8 Replies
9. Shell Programming and Scripting
Hi Folks,
I have a file with 2 columns TAB delimited and I want to add '1' to the first column and subtract '-1' from the second column.
What I have tried so far is;
awk -F"\t" '{ $1-=1;$2+=1}1' OFS='\t' file
File
0623 0623
0624 0624
0643 0643
1059 1037
1037 1037
1038 1038... (2 Replies)
Discussion started by: pshields1984
2 Replies
10. UNIX for Beginners Questions & Answers
Hi All,
I have a CSV file which is as below. Basically I need to take the year column in it and find if the year is >= 20152 . If that is then I should subtract all values by 6. In the below example in description I am having number mentioned as YYWW so I need to subtract those by -5. Whereever... (8 Replies)
Discussion started by: arunkumar_mca
8 Replies
LEARN ABOUT PHP
px_insert_record
PX_INSERT_RECORD(3) PX_INSERT_RECORD(3)
px_insert_record - Inserts record into paradox database
SYNOPSIS
int px_insert_record (resource $pxdoc, array $data)
DESCRIPTION
Inserts a new record into the database. The record is not necessarily inserted at the end of the database, but may be inserted at any
position depending on where the first free slot is found.
The record data is passed as an array of field values. The elements in the array must correspond to the fields in the database. If the
array has less elements than fields in the database, the remaining fields will be set to null.
Most field values can be passed as its equivalent php type e.g. a long value is used for fields of type PX_FIELD_LONG, PX_FIELD_SHORT and
PX_FIELD_AUTOINC, a double values is used for fields of type PX_FIELD_CURRENCY and PX_FIELD_NUMBER. Field values for blob and alpha fields
are passed as strings.
Fields of type PX_FIELD_TIME and PX_FIELD_DATE both require a long value. In the first case this is the number of milliseconds since mid-
night. In the second case this is the number of days since 1.1.0000. Below there are two examples to convert the current date or timestamp
into a value suitable for one of paradox's date/time fields.
Note
This function is only available if pxlib >= 0.6.0 is used.
PARAMETERS
o $pxdoc
- Resource identifier of the paradox database as returned by px_new(3).
o $data
- Associated or indexed array containing the field values as e.g. returned by px_retrieve_record(3).
RETURN VALUES
Returns FALSE on failure or the record number in case of success.
EXAMPLES
Example #1
Set the date/time fields in a paradox database to the current date/time
<?php
$px = px_new();
$fp = fopen("test.db", "w+");
px_create_fp($px, $fp, array(array("timestamp", "@"), array("time", "T"), array("date", "D")));
$curdate = getdate();
$jd = gregoriantojd($curdate["mon"], $curdate["mday"], $curdate["year"]);
$days = $jd - 1721425; /* Number of days between 1.1.4714 b.c. and 1.1.0000 */
$secs = $curdate["hours"]*3600 + $curdate["minutes"]*60 + $curdate["seconds"];
px_insert_record($px, array($days*86400000.0 + $secs*1000.0, $secs*1000.0, $days));
$curtimestamp = microtime(true);
$days = (int) ($curtimestamp/86400);
$secs = $curtimestamp - ($days * 86400.0);
$days += 2440588; /* Number of days between 1.1.4714 b.c. and 1.1.1970 */
$days -= 1721425; /* Number of days between 1.1.4714 b.c. and 1.1.0000 */
px_insert_record($px, array($days*86400000.0 + $secs*1000.0, $secs*1000.0, $days));
for($i=0; $i<2; $i++) {
$rec = px_retrieve_record($px, $i);
echo px_timestamp2string($px, $rec["timestamp"], "n/d/Y H:i:s")."
";
echo px_date2string($px, $rec["date"], "n/d/Y")."
";
}
px_close($px);
px_delete($px);
?>
The above example will output:
2/21/2006 21:42:30
2/21/2006
2/21/2006 20:42:30
2/21/2006
The Julian day count as passed to jdtogregorian(3) has a different base of 1.1.4714 b.c. and must therefore be calculated by adding
1721425 to the day count used in the paradox file. Turning the day count into a timestamp is easily done by multiplying with 86400000.0 to
obtain milli seconds.
SEE ALSO
px_update_record(3)
PHP Documentation Group PX_INSERT_RECORD(3)