Sponsored Content
Full Discussion: Compose variable name
Top Forums Shell Programming and Scripting Compose variable name Post 302192885 by Annihilannic on Thursday 8th of May 2008 04:51:48 AM
Old 05-08-2008
Ah, apologies, I put in an extra $ by mistake and missed a _.

Code:
eval "LISTEN_PORT"$CRT=$LPORT
...
eval echo "\$LISTEN_PORT$CRT"

This User Gave Thanks to Annihilannic For This Post:
 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Sed variable substitution when variable constructed of a directory path

Hello, i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem. my var1 is a string constructed like this: filename1 filerev1 filepath1 my var2 is another string constructed like this: filename2 filerev2 filepath2 when i do... (2 Replies)
Discussion started by: alrinno
2 Replies

2. Shell Programming and Scripting

Insert a line including Variable & Carriage Return / sed command as Variable

I want to instert Category:XXXXX into the 2. line something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong: sed "2i\\${n}Category:$cat\n" Sample: Titel Blahh Blahh abllk sdhsd sjdhf Blahh Blah Blahh Blahh Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies

3. Shell Programming and Scripting

How to define a variable with variable definition is stored in a variable?

Hi all, I have a variable say var1 (output from somewhere, which I can't change)which store something like this: echo $var1 name=fred age=25 address="123 abc" password=pass1234 how can I make the variable $name, $age, $address and $password contain the info? I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies

4. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

5. Shell Programming and Scripting

Variable not found error for a variable which is returned from stored procedure

can anyone please help me with this: i have written a shell script and a stored procedure which has one OUT parameter. now i want to use that out parameter as an input to the unix script but i am getting an error as variable not found. below are the unix scripts and stored procedure... ... (4 Replies)
Discussion started by: swap21783
4 Replies

6. Red Hat

How to pass value of pwd as variable in SED to replace variable in a script file

Hi all, Hereby wish to have your advise for below: Main concept is I intend to get current directory of my script file. This script file will be copied to /etc/init.d. A string in this copy will be replaced with current directory value. Below is original script file: ... (6 Replies)
Discussion started by: cielle
6 Replies

7. Shell Programming and Scripting

awk: compose regex in variable and then use its contents like $0 ~ var

A question to the awk pundits: I was thinking about composing a regex in a variable and then use its contents like $0 ~ var instead of $0 ~ /r/. Sort of indirection. Did someone run into this? Is it possible at all? (3 Replies)
Discussion started by: RudiC
3 Replies

8. Shell Programming and Scripting

[Solved] How to increment and add variable length numbers to a variable in a loop?

Hi All, I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Discussion started by: danish0909
5 Replies

9. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
eval(n) 						       Tcl Built-In Commands							   eval(n)

__________________________________________________________________________________________________________________________________________________

NAME
eval - Evaluate a Tcl script SYNOPSIS
eval arg ?arg ...? _________________________________________________________________ DESCRIPTION
Eval takes one or more arguments, which together comprise a Tcl script containing one or more commands. Eval concatenates all its argu- ments in the same fashion as the concat command, passes the concatenated string to the Tcl interpreter recursively, and returns the result of that evaluation (or any error generated by it). Note that the list command quotes sequences of words in such a way that they are not further expanded by the eval command. EXAMPLES
Often, it is useful to store a fragment of a script in a variable and execute it later on with extra values appended. This technique is used in a number of places throughout the Tcl core (e.g. in fcopy, lsort and trace command callbacks). This example shows how to do this using core Tcl commands: set script { puts "logging now" lappend $myCurrentLogVar } set myCurrentLogVar log1 # Set up a switch of logging variable part way through! after 20000 set myCurrentLogVar log2 for {set i 0} {$i<10} {incr i} { # Introduce a random delay after [expr {int(5000 * rand())}] update ;# Check for the asynch log switch eval $script $i [clock clicks] } Note that in the most common case (where the script fragment is actually just a list of words forming a command prefix), it is better to | use {*}$script when doing this sort of invocation pattern. It is less general than the eval command, and hence easier to make robust in | practice. The following procedure acts in a way that is analogous to the lappend command, except it inserts the argument values at the start of the list in the variable: proc lprepend {varName args} { upvar 1 $varName var # Ensure that the variable exists and contains a list lappend var # Now we insert all the arguments in one go set var [eval [list linsert $var 0] $args] } However, the last line would now normally be written without eval, like this: | set var [linsert $var 0 {*}$args] | SEE ALSO
catch(n), concat(n), error(n), interp(n), list(n), namespace(n), subst(n), tclvars(n), uplevel(n) KEYWORDS
concatenate, evaluate, script Tcl eval(n)
All times are GMT -4. The time now is 05:08 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy